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julsineya [31]
2 years ago
8

It rained on exactly 7 of the days during Jane's trip. On each day that it rained, it rained either in the morning or in the aft

ernoon but not both. There were exactly 5 afternoons when it did not rain and exactly 6 mornings when it did not rain. How many days did the trip last?
Mathematics
1 answer:
Lerok [7]2 years ago
8 0

Answer:

The trip lasted 9 days.

Step-by-step explanation:

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<h3>1.Area of the parallelogram= 288 square units</h3><h3>2.Area of the parallelogram=45 m^2</h3><h3>3.Area of the trapezoid   = 34 square in.</h3><h3>4.Area of the trapezoid = 8 square ft</h3><h3>5.Area of the rhombus= 27 square cm</h3><h3>6.Area of the rhombus= 108 square in</h3><h3>7.The area of the desktop is  = 1200 square in</h3><h3>8.The area of the rhombus is =84 cm^2</h3><h3>9.Area of the trapezoid  = 240 square ft</h3>

Step-by-step explanation:

1.

Base =16 ft and Height = 18 ft

Area of the parallelogram = base × height

                                       =16× 18 square units

                                       = 288 square units

2.

Base = 9 m and height = 5 m

Area of the parallelogram = base × height

                                        =(9×5) m^2

                                         =45 m^2

3 .

Height = 4 in and parallel sides are 12 in and 5 in

Area of the  trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                            =\frac{1}{2} \times (12+5) \times 4 square in.

                             = 34 square in.

4.

Height = 2 ft  and parallel sides are 2 ft and 6 ft

Area of the trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                              =\frac{1}{2} \times (2+6) \times 2 square ft

                              = 8 square ft

5.

Diagonals are 6 cm and 9 cm.

Area of the rhombus = \frac{1}{2}\times {\textrm{product of diagonals}

                               =\frac{1}{2 } \times 6\times 9 square cm

                               = 27 square cm

6. Diagonals are 12 in and 18 in

Area of the rhombus = \frac{1}{2}\times {\textrm{product of diagonals}

                               =\frac{1}{2 } \times 12\times 18 square in

                               = 108 square in

7. Given a desktop in the shape of a parallelogram has a base 30 in. and a height of 40 in

The area of the desktop is = (30 × 40 ) square in

                                            = 1200 square in

8. Given , a rhombus has one diagonal that is 14 cm and other diagonal 12 cm.

The area of the rhombus = \frac {1}{2} \times 14 \times 12 cm^2

                                         =84 cm^2

9.Given , the base of trapezoid are 24 ft  and 16 ft and height is 12 ft

Area of the trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                                    = \frac{1}{2} \times (24+16) \times 12 square ft

                                     = 240 square ft

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Answer:

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Step-by-step explanation:

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