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julsineya [31]
3 years ago
8

It rained on exactly 7 of the days during Jane's trip. On each day that it rained, it rained either in the morning or in the aft

ernoon but not both. There were exactly 5 afternoons when it did not rain and exactly 6 mornings when it did not rain. How many days did the trip last?
Mathematics
1 answer:
Lerok [7]3 years ago
8 0

Answer:

The trip lasted 9 days.

Step-by-step explanation:

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Maia's calculator displays a number as 9.125 E10. What is this number in standard form?
melomori [17]
9.125 E10 is the same as 9.125 × 10¹⁰ in standard form. 
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3 years ago
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Use the linear combination method to solve the system of equations. Explain each step of your solution. 2x-3y=13 4x-y=-9
Tems11 [23]

2x -3y = 13

4x -y = -9

Multiply the second equation by -3 to make the coefficient of Y opposite the first equation.

4x -y = -9 x -3 = -12x + 3y = 27

Now add this to the first equation:

2x -12x = -10x

-3y +3y = 0

13 +27 = 40

Now you have :

-10x = 40

Divide each side by -10:

x = 40 / -10

x = -4

Now you have a value for x, replace that into the first equation and solve for y:

2(-4) - 3y = 13

-8 - 3y = 13

Add 8 to both sides:

-3y = 21

Divide both sides by -3:

y = 21/-3

y = -7

Now you have X = -4 and y = -7

(-4,-7)

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3 years ago
HELP WITH MY ANNOYING MIDDLE SCHOOL MATH PLEASEEEEEE!!!!!!<br> WILL GIVE BRAINLIEST!!!!!
AlladinOne [14]

Answer:

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Step-by-step explanation:

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Volume of a cone = r²h,
inessss [21]

Answer:

7.5 m           457.5\pi m^{2}

Step-by-step explanation:

First, visualize the original cone and the smaller cone as overlapping similar triangles. The scale factor of the original cone to the smaller cone is 50:40, so if the smaller cone has a radius of 6 m, then the radius of the original cone would be 7.5 m.

The volume of the frustum is the volume of the original cone minus the volume of the smaller cone. The formula for the volume of a cone is V = \frac{1}{3} \pi r^{2}h.

Original Cone = \frac{1}{3} \pi r^{2}h = \frac{1}{3} \pi *7.5^{2}*50 = 937.5\pi

Smaller Cone = \frac{1}{3} \pi r^{2}h =  \frac{1}{3} \pi *6^{2}*40 = 480\pi

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6 0
2 years ago
PLEASE HELP 10pts
Veronika [31]

Answer:

Hence the function which has the smallest minimum is: h(x)

Step-by-step explanation:

We are given function f(x) as:

  • f(x) = −4 sin(x − 0.5) + 11

We know that the minimum value attained by the sine function is -1 and the maximum value attained by sine function is 1.

so the function f(x) receives the minimum value when sine function attains the maximum value since the term of sine function is subtracted.

Hence, the minimum value of f(x) is: 11-4=7 ( when sine function is equal to 1)

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x    y

−2   14

−1   9

 0   6

  1   5

 2   6

 3   9

 4   14

Hence, the minimum value attained by h(x) is 5. ( when x=1)

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so, the equation will be:

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Hence the function g(x) is given as:

g(x)=x^2-6x+15

So,the minimum value attained by g(x) could be seen from the graph is at the point (3,6).

Hence, the minimum value attained by g(x) is 6.

Hence the function which has the smallest minimum is h(x)

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3 years ago
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