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uysha [10]
3 years ago
14

Find the volume of a cylinder with the diameter of 8 in and height that is three times the radius.

Mathematics
1 answer:
gavmur [86]3 years ago
5 0

Answer:

<h2>hope it helps you see the attachment for further information ✌✌✌✌✌✌</h2>

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In a study of
o-na [289]
We know that:
Mean = 82 mm and SD = 10 mm ( standard deviation )
82 - 3 * SD = 82 - 3 * 10 = 82 - 30 = 52 mm
82 + 3 * SD = 82 + 3 * 10 = 82 + 30 = 112 mm
Population between 52 and 112 mm is within +/- 3 standard deviations from the mean.
By the 66- 95 - 99.7 % rule it is: 99.7% of the test group.
0.977 * 500 = 498.5
Answer:
99.7 % of the test group have a diastolic pressure between 52 and 112 mm, or 498 men. 
5 0
3 years ago
A bag of marbles had 18 green marbles and the rest were blue. For a game, 5/6 of the 18
stepan [7]

Answer:

A 5 B 2 C3

Step-by-step explanation:

6 0
3 years ago
OKAY i CANT EVEN FIGURE THIS ONE OUT NEED HELP.<br> -3 (5 – 2y)
inessss [21]

negative multiplied by positives = negative numbers

3 x 5 = -15

negative multiplied by a negative = a positive number

-3 x -2y = +6y

so combine both gets -15 +6y

or a better way to write it is 6y-15

5 0
3 years ago
Draw three rectangles that 2 cm long and 1 cm wide. On each rectangle show a different way to divide the rectangle in half. Then
andrew11 [14]
You can draw the 3 rectangles with these measurements then divide one horizontally one vertically and one slanted from one top corner to one bottom corner
5 0
3 years ago
For which rational expression is 8 an excluded value ? check all that apply
denis23 [38]

<u>Answer:</u>

The correct answer options are C. \frac{x^2+5}{x-8} and D. \frac{x^2-x-56}{x^2-64}.

<u>Step-by-step explanation:</u>

The values which make the denominator equal to zero are called the excluded values.

Here, we can substitute 8 for x and check if it makes the denominator 0.

\frac{x-8}{x+8} = \frac{8-8}{8+8} =\frac{0}{16} =0

\frac{x-2}{x^2-4} = \frac{8-2}{8^2-4} =\frac{6}{60} =\frac{1}{10}

\frac{x^2+5}{x-8} = \frac{8^2+5}{8-8} =\frac{69}{0}

\frac{x^2-x-56}{x^2-64} = \frac{8^2-8-56}{8^2-64} = \frac{0}{0} =0

\frac{8x^2-2}{x^2-16} = \frac{8(8)^2-2}{8^2-16} =\frac{510}{48}

7 0
3 years ago
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