The square root of 75/3 is a irrational number
Answer:
Step-by-step explanation:
6v + 12b = 504 eq1
2v + 5b = 204 eq2
6v + 15b = 612 eq2 times 3
0 -3b = 504 - 612 subtraction of the two bolded eqs
-3b = -108 solve for b
b = 36
Another way to solve the problem
6v + 12b = 504 I would eliminate the v term by multiplying the bottom
2v + 5b = 204 equation by -3 on BOTH sides and then add the two eqs
2v + 5b = 204
-3(2v + 5b) = -3(204)
-6v - 15b = -612
6v + 12b = 504
-6v - 15b = -612 add the like terms
(6v + (-6v)) + (12b + (-15b) = 504 + (-612)
(6v -6v)) + (12b - 15b) = 504 - 612)
0 + -3b = - 108 solve for b divide both sides by -3
b = -108/-3
b = 36
use eq 2v + 5b = 204 to solve for v and knowing b = 36
2v + 5b = 204 b=36
2v + 5(36) = 204 substract 5 times 36 from both sides
2v = 204 - 180
v = 24 / 2
v = 12
NOW CHECK the values for b and v using the OTHER eq
6v + 12b = 504
6(12) + 12(36) = 504
72 + 432 = 504
504 = 504 IT CHECKS
We analyze the linear function to find that it has equation
. Drawing the line, we find that it
will intersect the circle at negative and positive x-coordinates.We can prove this by
substituting into the given equation:
Hence,
or
, so there are both positive and negative values for
.
Answer:
table b'
Step-by-step explanation:
