Slope-intercept form:
y=mx+b
m=slope
b=y-intercept
2x+3y=6
3y=-2x+6
y=-2/3 x+6/3
y=-2/3 x+2
Answer: the line in slope-intercept form would be:
y=-2/3 x+2
Answer:
Therefore the correct assembling is
3.∠DAC ≅ ∠BCA 3. Alternate interior Angles are Equal as AD || BC.
Step-by-step explanation:
Given:
AD ≅ BC and AD || BC
To Prove:
ABCD is a Parallelogram
Proof:
Alternate Interior Angles Theorem :
"When two parallel lines are cut by a transversal , the resulting alternate interior angles are congruent.
Here AD || BC and the transversal is AC
Statement Reasons
1. AD ≅ BC . 1. Given
2. AD || BC 2. Given
3.∠DAC ≅ ∠BCA 3. Alternate interior Angles are Equal as AD || BC.
Therefore the correct assembling is
3.∠DAC ≅ ∠BCA 3. Alternate interior Angles are Equal as AD || BC.
Answer:
The probability that the pair consists of a female junior and a male sophomore is 0.096
Step-by-step explanation:
No of male juniors=4
No of female juniors=10-4=6
No of female sophomores=5
No of male sophomores=13-5=8
As per question,
Probability that the pair consists of a female junior and
a male sophomore =
=0.096
Therefore, the probability that the pair consists of a female junior and a male sophomore is 0.096
Answer:
Step-by-step explanation:
Given:
ΔCAD and ΔCBD
∠A ≅∠B (Angle)
AD ≅BD (Side)
From the graph we see that
CD≅CD (Side)
because of reflexive propriety ( a line segment is congruent with itself)
If you put in order those congruencies we have SSA witch does NOT prove congruence.
we not use SAS because the angle between the sides is not congruent
