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Blababa [14]
2 years ago
10

Please help! need answers in order to move on:) will give brainliest if you are correct!

Mathematics
1 answer:
shepuryov [24]2 years ago
5 0

Answer:

1) x^{2/3}

3 → index

\sqrt[3]{x^{2} }

Index: 3

<u>----------------</u>

2) 7^{5/4}

=\sqrt[4]{7^{5} }

=(\sqrt[4]{7})^{5}

<u>----------------</u>

3) \sqrt[7]{2^{3} }

=(2^{3} )^{1/7}  [\sqrt[x]{n} =n^{1/n} ]

=2^{3/7}

<u>----------------</u>

3) \sqrt[12]{8^{4} }

y=(8^{4} )^{1/12}

y=(8)^{1/3}

y=(2)^{3\times 1/3}

y=2

<u>------------------</u>

4) 128^{3/7}

=\sqrt[7]{2\times 2\times2\times 2\times 2\times2\times 2}

=(2)^{3}

=8

<u>----------------------</u>

<u>OAmalOHopeO</u>

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Answer:

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first, 16x3=48

and then 48x2=96

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3 0
3 years ago
Can someone explain to me how to do this and the answer for them too because I do not understand these geometry proofs!!
Neko [114]

Answer:

Statement                        Reasoning

LM=NO                             Given

∠LMO≅∠NOM.                 Given

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6 0
2 years ago
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Marysya12 [62]
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3 years ago
Find the solution r(t)r(t) of the differential equation with the given initial condition: r′(t)=⟨sin9t,sin6t,9t⟩,r(0)=⟨4,6,3⟩
klemol [59]

\mathbf r'(t)=\langle\sin9t,\sin6t,9t\rangle


\mathbf r(t)=\displaystyle\int\mathbf r'(t)\,\mathrm dt


\mathbf r(t)=\left\langle\displaystyle\int\sin9t\,\mathrm dt,\int\sin6t\,\mathrm dt,\int9t\,\mathrm dt\right\rangle


\displaystyle\int\sin9t\,\mathrm dt=\frac19\cos9t+C_1

\displaystyle\int\sin6t\,\mathrm dt=\frac16\cos6t+C_2

\displaystyle\int9t\,\mathrm dt=\frac92t^2+C_3


With the initial condition \mathbf r(0)=\langle4,6,3\rangle, we find


\dfrac19\cos0+C_1=4\implies C_1=\dfrac{35}9

\dfrac16\cos0+C_2=6\implies C_2=\dfrac{35}6

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So the particular solution to the IVP is


\mathbf r(t)=\left\langle\dfrac19\cos9t+\dfrac{35}9,\dfrac16\cos6t+\dfrac{35}6,\dfrac92t^2+3\right\rangle

4 0
3 years ago
4 of 7<br> June rolls a fair dice 234 times.<br> How many times would June expect to roll a one?
alexandr402 [8]

Answer: 39 times

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7 0
2 years ago
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