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Likurg_2 [28]
4 years ago
6

How to simple form please

Mathematics
2 answers:
Elan Coil [88]4 years ago
7 0

The solution of the given questions are below,

1) (x+5)(x-2)

2) (x-3)(x+2)

3) (x+5)(x+3)

4) (x-4)(x-3)

Step-by-step explanation:

1) x^{2} + 3x -10

= x^{2} + 5x - 2x -10

= x( x+5) -2(x+5)

=(x+5)(x-2)

2) x^{2} - x - 6

= x^{2} - 3x +2x - 6

= x(x -3) +2( x-3)

=(x-3)(x+2)

3) x^{2} +8x +15

= x^{2} +5x + 3x +15

= x(x+5) +3(x+5)

= (x+5)(x+3)

4) x^{2} -7x +12

= x^{2} - 4x -3x +12

= x(x-4) -3(x -4)

=(x-4)(x-3)

Lena [83]4 years ago
6 0

Answer:

roots are -3,2 for 2)

roots are 5,3 for 3)

roots are -3,-4 for 4)

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Step-by-step explanation:

3.50*6=21

21 is the answer

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The weight of an adult blue whale is 9 × 104 kilograms; the weight of an elephant is 3 × 103 kilograms. How many times heavier i
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Find the coordinates of the circumcenter for ∆DEF with coordinates D(1,3) E (8,3) and F(1,-5).
NemiM [27]

Let the coordinates of the circumcentre O of the triangle DEF be (x, y). Circumcentre of a triangle is equidistant from each of the vertices.

1. Distance OD=distance OE, then:

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2. Distance OD=distance OE, then:

(x-1)^2+(y-3)^2=(x-1)^2+(y+5)^2.

Solve the system:

\left\{\begin{array}{l}          (x-1)^2+(y-3)^2=(x-8)^2+(y-3)^2 \\          (x-1)^2+(y-3)^2=(x-1)^2+(y+5)^2         \end{array}\right.,

\left\{\begin{array}{l}          x^2-2x+1+y^2-6y+9=x^2-16x+64+y^2-6y+9 \\          x^2-2x+1+y^2-6y+9=x^2-2x+1+y^2+10y+25         \end{array}\right.,

\left\{\begin{array}{l}          14x=63 \\          -16y=16         \end{array}\right..

Then

x=\dfrac{63}{14} =\dfrac{9}{2} =4.5,\\  \\ y=-1.

Answer: the coordinates of the circumcenter for ∆DEF are x=4.5, y=-1.


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8x - 3(2x - 4) = 3(x-6)
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Answer:

X=30

Step-by-step explanation:

...

5 0
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