Answer:
hmmmmm i dont rlly understand this but ima guess tho i think a and c or d
Step-by-step explanation:
Answer:
The solutions of the equation are -41.8° , 0.0° , 41.8°
Step-by-step explanation:
∵ 3 sin²Ф - 2 sinФ = 0 is a quadratic function
∵ The domain of the function is -90° ≤ Ф ≤ 90°
- Lets take sinФ as a common factor
∴ sinФ (3 sinФ - 2) = 0
- Two terms multiplied by each other = 0
∴ One of them must be equal zero
∴ sinФ = 0 or 3 sinФ - 2 = 0
- If sinФ = 0 ⇒ Ф = 0.0°
- If 3 sinФ - 2 = 0 ⇒ 3 sinФ = 2 ⇒ sin Ф = 2/3
∵ sinФ 2/3
∴ Ф = 41.8° ⇒ Ф ≤ 90° (in first quadrant)
∵ -90° ≤ Ф ≤ 90°
∴ Ф = -41.8° ⇒ Ф ≥ -90° (in fourth quadrant)
∴ The solutions of the equation are -41.8° , 0.0° , 41.8°
8-2i is their total score. You can't combine the imaginary numbers and real numbers.
Check the picture below.
now, we have a triangle with all three sides, thus we can use Heron's Area Formula on the triangle.
![\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=10\\ b=26.695\\ c=22\\ s=29.3475 \end{cases} \\\\\\ A=\sqrt{29.3475(29.3475-10)(29.3475-26.695)(29.3475-22)} \\\\\\ A=\sqrt{29.3475(19.3475)(2.6525)(7.3475)}\implies A\approx \sqrt{11066.007} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill A\approx 105.195~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BHeron%27s%20area%20formula%7D%20%5C%5C%5C%5C%20A%3D%5Csqrt%7Bs%28s-a%29%28s-b%29%28s-c%29%7D%5Cqquad%20%5Cbegin%7Bcases%7D%20s%3D%5Cfrac%7Ba%2Bb%2Bc%7D%7B2%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D10%5C%5C%20b%3D26.695%5C%5C%20c%3D22%5C%5C%20s%3D29.3475%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20A%3D%5Csqrt%7B29.3475%2829.3475-10%29%2829.3475-26.695%29%2829.3475-22%29%7D%20%5C%5C%5C%5C%5C%5C%20A%3D%5Csqrt%7B29.3475%2819.3475%29%282.6525%29%287.3475%29%7D%5Cimplies%20A%5Capprox%20%5Csqrt%7B11066.007%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20A%5Capprox%20105.195~%5Chfill)
Answer:
1/6+2/6=3/6
1/2
Step-by-step explanation:
