Answer:
Step-by-step segment dc bisects segment ab, then point d is equidistant from points a and b because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects. if segment dc bisects segment ab, then point d is equidistant from points a and b because congruent parts of congruent triangles are congruent. if segment ad bisects segment ab, then point d is equidistant from points a and b because a point on a perpendicular bisector is equidistant from:
For the 1st one we need to solve x. x-y=2 step1: x-y+y=2+y answer: x=y+2
Hello,
Assume Ax+By+Cz+D=0 the plane 's equation.
p=(0,0,0)==>A*0+B*0+C*0+D=0==>D=0
q=(0,1,0)==>A*0+B*1+C*0+0=0==>B=0
r=(1,2,3)==>A*1+0*2+C*3+0=0==>A=-3C
Let C=1==>A=-3
An equation of the plane is -3x+z=0
You get: (1x20)/(5x20)=20/100=20%.
Hope i helped you! :)
Answer:
The answer is A
Step-by-step explanation:
Supplementary angles are angles which add up to 180°
∠1 and ∠3 add up to 180°, so they are supplementary.
