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mote1985 [20]
3 years ago
8

Solve for x................

Mathematics
2 answers:
alexandr402 [8]3 years ago
8 0

Answer:

Option C

x={1(+/-)2\sqrt{3}}


Step-by-step explanation:

we have

x^{2}-2x-11=0

we know that


The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to


x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}


in this problem we have


x^{2}-2x-11=0

so


a=1\\b=-2\\c=-11


substitute

x=\frac{-(-2)(+/-)\sqrt{-2^{2}-4(1)(-11)}} {2(1)}


x=\frac{2(+/-)\sqrt{4+44}} {2}


x=\frac{2(+/-)\sqrt{48}} {2}


x=\frac{2(+/-)4\sqrt{3}} {2}


x={1(+/-)2\sqrt{3}}


prisoha [69]3 years ago
7 0

Answer:

Choice C is correct answer.

Step-by-step explanation:

Given equation is :

x²-2x-11= 0

ax²+bx+c = 0 is general quadratic equation.

x = (-b±√b²-4ac) / 2a is quadratic formula to solve quadratic equation.

Comparing general equation with given equation,we get

a = 1 , b = -2 and c = -11

Putting above values in quadratic formula ,we get

x = (-(-2)±√(-2)²-4(1)(-11)) / 2(1)

x = (2±√4+44) / 2

x = (2±√48) / 2

x = (2±4√3) / 2

x = 2(1±2√3) / 2

x = 1±2√3

Hence, the solution of x²-2x-11 =0 is 1±2√3.


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