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Lina20 [59]
3 years ago
7

Round to one decimal place (BRAINLIEST)

Mathematics
1 answer:
Semmy [17]3 years ago
8 0

Answer:

4.3

Step-by-step explanation:

Apply trigonometric ratios to find the answer.

Firstly, we need to find the measure of angle theta. In order to do this, we will use triangle BAD.

From angle theta, the trigonometric ratio sine can be used:

sinθ = \frac{4.1}{5.3}

After we find the value, we take the inverse sine of it and the result is approximately 50.7 degrees.

Now, knowing that angles BAD and CAD are the same, we can solve for CD using trigonometric ratio sine.

sin50.7 = opposite/hypotenuse

sin50.7 = CD/5.5

sin50.7 * 5.5 = CD

4.3 ≈ CD

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HACTEHA [7]

Answer:

119.43cm^2

Step-by-step explanation:

The computation of the area of the shaded region is shown below:

As we know that

= Area of the rectangle - Area of the circle

where,

Area of rectangle is

= length \times breadth

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= 132 cm^2

And, the area of the circle is

=  \pi\times r^2\\\\ = \frac{22}{7} \times 2^2\\\\ = \frac{88}{7} cm^2

Now the area of the shaded region is

= 132 cm^2- \frac{88}{7}cm^2

= 119.43cm^2

We simply deduct the area of the circle from the area of the rectangle so that the area of the shaded region.

7 0
3 years ago
Six times a number equals 3 times the number, increased by 12. Find the number
tino4ka555 [31]

Answer:

x=4

Step-by-step explanation:

"A number" can be rewritten as X:

6x=3x+12

1) subtract 3x on both sides:

3x=12

2) divide both sides by 3:

x=4

4 0
3 years ago
(Geometry Question) : Given the points A(-3, -4) and B(2, 0), find the coordinates of the point P on directed line segment AB th
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3 years ago
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For which of the following decreasing functions f does (f−1)′(10)=−1/8
Oduvanchick [21]

Recall the inverse function theorem: if f(x) has an inverse, and if f(a) = b and a = f⁻¹(b), then

f⁻¹(f(x)) = x   ⇒   (f⁻¹)'(f(x)) • f'(x) = 1   ⇒   (f⁻¹)'(f(x)) = 1/f'(x)

⇒   (f⁻¹)'(b) = 1/f'(a)

Let b = 10. Then pick the function f(x) such that f(a) = 10 and f'(a) = -8 for some number a.

7 0
2 years ago
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