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vovangra [49]
3 years ago
13

Apply the Gram Schmidt orthogonalization process for decomposition for the matrix = (1 −2 3 5)

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
6 0
23 or its 34 percent off the right nw nw is the 7th is
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Round 23,879 to the nearest thousand
Vlad [161]
23, 879 to the nearest thousand.

The thousand digit is  the 3, and we look at the digit after 3, which is 8, since 8 is more than 5, we round up the 3 to 4.

Therefore 23, 879 to the nearest thousand ≈ 24, 000

I hope this explains it.
3 0
2 years ago
ASAP. Can someone help me find the percentage of these please, I can't figure it out. (Pic below)
atroni [7]

Answer:

Interphase: 55.56%

Prophase: 27.78%

Metaphase: 8.33%

Anaphase: 5.56%

Telophase: 2.78%

Step-by-step explanation:

All you need to do is follow the instructions. To get the percentage, all you need to do is divide the part by the whole then multiply it by 100%.

\dfrac{Part}{Whole}\times 100\%

Now let's take your problem:

Number of cells in interphase:

20 this is the part and the whole would be the total cells, which is 36. Now we insert that into our equation:

\dfrac{20}{36}\times 100\%=0.5556\times100\%=55.56\%

So now we apply the same to the rest:

Prophase:

\dfrac{10}{36}\times 100\%=0.2778\times100\%=27.78\%

Metaphase:

\dfrac{3}{36}\times 100\%=0.0833\times100\%=8.33\%

Anaphase:

\dfrac{2}{36}\times 100\%=0.0556\times100\%=5.56\%

Telophase:

\dfrac{1}{36}\times 100\%=0.0278\times100\%=2.78\%

4 0
3 years ago
During the summer, the population of spring lake is 30,155. During the winter, the population drops down to 13,876. How many peo
aleksley [76]
30,155-13,876=16,279
16,279 people spend on the summer months in spring lake.
3 0
3 years ago
Read 2 more answers
A low P-Value in ANOVA table mean that the population mean of each treatment effects are different. the population mean of at le
Verizon [17]

Answer:

The population mean of at least one treatment effect are different.

Step-by-step explanation:

An analysis of variance (ANOVA) is conducted in order to determine if there are significant differences between the values of the population mean with respect to the response variable for the domains that under the effects of different treatments. A low p-value leads to reject the null hypothesis of the following hypothesis system:

H_0: \mu_1=\mu_2=...=\mu_k\\\\\\H_a: \mu_i \neq\mu_j, for $ for some i, j between 1 and k.$

Rejecting H0 means that this hypothesis is false and, in turn, allows us to conclude that the population mean of one of the domains is different from the others.

4 0
3 years ago
If (-5x^5) (a) = 25x^7 + 100x^5, find a
sweet-ann [11.9K]
(-5x^5)(a) = 25x^7 + 100x^5
<u>+5x^5                         +5x^5</u>
             a = 25x^7

4 0
2 years ago
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