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4 years ago

Degree 3 polynomial with integer coefficients with zeros 7i and 9/5 Write it as a polynomial

Mathematics

1 answer:

otez555 [7]4 years ago

5 0

Answer:

f(x) = 5x^3 - 9x^2 + 245x - 441.

Step-by-step explanation:

Complex zeros are in conjugate pairs so the third zero is -7i.

In factor form we have:

f(x) = (x - 7i)(x + 7i)(5x - 9)

= (x^2 - 49i)^2)(5x - 9)

= (x^2 + 49)(5x - 9)

= 5x^3 - 9x^2 + 245x - 441.

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Can someone help me

Lemur [1.5K]

Multiplying fractions is just multiplying the numerators together and the denominators together.

$\sf\dfrac{4}{7}\times\dfrac{1}{4}\rightarrow\dfrac{4\times 1}{7\times 4}\rightarrow\dfrac{4}{28}\rightarrow\dfrac{1}{7}$

$\sf\dfrac{4}{7}\times\dfrac{1}{6}\rightarrow\dfrac{4\times 1}{7\times 6}\rightarrow\dfrac{4}{42}\rightarrow\dfrac{2}{21}$

To find out which one is bigger, we need a common denominator. The LCM of 7 and 21 is 21, so convert the first fraction into a denominator of 21. 7 goes into 21 three times, multiply this to the numerator and denominator:

$\sf\dfrac{1}{7}\rightarrow\dfrac{1\times 3}{7 \times 3}\rightarrow\dfrac{3}{21}$

Now just compare the numerators to see which one is bigger.

$\sf\dfrac{3}{21}>\dfrac{2}{21}$ therefore, $\sf\dfrac{4}{7}\times\dfrac{1}{4}>\dfrac{4}{7}\times\dfrac{1}{6}$

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What is the correct equation to solve for X?

Vanyuwa [196]

It’s the second option
sin(45)=13/x

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3 years ago

Awarding road contracts. A state Department of Transportation (DOT) recently claimed that each of five bidders received equal co

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Answer:

a) Hence, the probability of this event occurring if, in fact, the DOT's claim is true

= 3/10 = 0.3

Step-by-step explanation:

a) The concept applied here is combinatorics ; nCr = n!/(n - r)!r!

we are told that out of 5bidders, Three of the bidders were large construction conglomerates

and two were small specialty contractors.

selecting two recipients with tree of the bidders were large construction conglomerates 3C2

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Similarly, selecting the two small casualty contractor from the total of 5bidders = 5C2

= 5!/(5-2)!2!

= 10

Hence, the probability of this event occurring if, in fact, the DOT's claim is true

= 3/10 = 0.3

b) if DOTs claim is not true ( probability of failure) = 1 - 0.3

= 0.7 , this value implies that the probability 0.3 is largely compatible and a compliment of the 0.7 and as such it is consistent with the DOTs claim that the selection was random.

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