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3 years ago

Someone answer my math question

Mathematics

1 answer:

nirvana33 [79]3 years ago

6 0

Answer:

y = 7x-5

Step-by-step explanation:

The slope is 7 and the y intercept is -5

We are to write the equation is slope intercept form

y= mx+b where m is the slope and b is the y intercept

y = 7x-5

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Write an expression for the perimeter of each regtangle in terms of its width?

ELEN [110]

Answer:

a (the length is twice the width)

Step-by-step explanation:

a(the length is twice the width)

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3 years ago

Please help because I'm getting confused, and please show step by step. :(

Westkost [7]

So lets just simplify them first
1 batch = 2 3/4 so...
11/4 cups

and you need to make 3 1/2 batch so..
7/2 batch

then you just multiply it...
11/4 x 7/2
=77/8
=9 5/8

so you will need 9 5/8 cups

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3 years ago

Which equation has no real solutions

Angelina_Jolie [31]

Answer:

second

Step-by-step explanation:

Δ=3²-4*1*4=9-16=-7

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2 years ago

How do you graph x-y-3=0

Neko [114]

Answer:

see explanation

Step-by-step explanation:

To graph the line, we require 2 points

Find the intercepts, that is where the graph crosses the x and y axes

To find the x- intercept let y = 0 in the equation and solve for x

x - 3 = 0 ( add 3 to both sides )

x = 3 ⇒ (3, 0 ) ← x- intercept

To find the y- intercept let x = 0 in the equation and solve for y

- y - 3 = 0 ( add 3 to both sides )

- y = 3 ( multiply both sides by - 1 )

y = - 3 ⇒ (0, - 3 ) ← y- intercept

Plot the points (3, 0) and (0, - 3) and draw a straight line through them

4 0

3 years ago

Daniel [21]

Answer:

$x=\sqrt{\frac{7(4+\sqrt{15})}{2}}$

Step-by-step explanation:

From the way it is written, the $x$ is outside the square root. I will rewrite it as:

$x\sqrt{5} =x\sqrt{3} +\sqrt{7}$

$x\sqrt{5}-x\sqrt{3}=\sqrt{7}$

$x(\sqrt{5} - \sqrt{3} )=\sqrt{7}$

$x= \frac{\sqrt{7} }{\sqrt{5} - \sqrt{3}} \implies \frac{\sqrt{7}(\sqrt{5} + \sqrt{3}) }{2}$

$x=\frac{1}{2} \sqrt{7} (\sqrt{5} + \sqrt{3} )$

$x=\frac{\sqrt{35}}{2} +\frac{ \sqrt{21}}{2}$

$x=\frac{\sqrt{35}+\sqrt{21}}{2}$

Multiply denominator and numerator by 3

$x=\frac{3\sqrt{35}+3 \sqrt{21}}{6}$

Factor $\sqrt{3}$

$\sqrt{3} (\sqrt{105}+3 \sqrt{7})$

$x=\frac{\sqrt{3} (\sqrt{105}+3 \sqrt{7})}{6}$

Divide denominator and numerator by $\sqrt{3}$

$x=\frac{\sqrt{105}+3 \sqrt{7}}{2\sqrt{3} }$

Let's rewrite it again

$x=\frac{\sqrt{ (\sqrt{105}+3 \sqrt{7})^2}}{\sqrt{12} }$

$x=\sqrt{ \frac{1}{12} \cdot (\sqrt{105}+3 \sqrt{7})^2}$

It is already in the form $\sqrt{\frac{a}{b} }$

Expanding the perfect square, we have

$63+42\sqrt{15}+105$

$\frac{63}{12} +\frac{42\sqrt{15}}{12} +\frac{105}{12}$

$\frac{21}{4} +\frac{7\sqrt{15}}{2} +\frac{35}{4}$

Factor $\frac{7}{2}$

$\frac{7}{2} (4+\sqrt{15} )$

Therefore,

$x=\sqrt{\frac{7}{2} \left(4+\sqrt{15} \right)}$

$x=\sqrt{\frac{7(4+\sqrt{15})}{2}}$

7 0

3 years ago

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