Question

The Probability that one bulb is red and one is yellow?

Answer 1

Answer:

$\frac{11}{39}$

Step-by-step explanation:

Given,

The number red bulb = 11,

Yellow bulb = 9,

Purple = 7,

Total bulbs = 11 + 9 + 7 = 27,

If two bulbs are taken,

Then, the probability that one bulb is red and one is yellow

$=\frac{^{11}C_1\times ^9C_1}{{27}^C_2}$

$=\frac{11\times 9}{\frac{27!}{2!\times 25!}}$

$=\frac{99}{\frac{27\times 26}{2}}$

$=\frac{99}{27\times 13}$

$=\frac{11}{39}$

Answer 2

I have a solution here where:

A bag of 27 Tulip bulbs contain 10 red tulip bulbs, 8 Yellow, and 9 purple tulip bulbs. 

Red- 
10/27= .37 
times 100 gives percentage 
=37% 

Yellow- 
8/27= .3 
times 100 gives percentage 
30%

You can use my solution in answering the question on your own!

I hope my answer has come to your help. Have a nice day ahead and may God bless you always!