nadu has finished 2/5 of his job in May, then finished 60% of the remaining job in June. How many percent of the job has he fini
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The graphs of f(x) and g(x) are transformed function from the function y = x^2
The set of inequalities do not have a solution
<h3>How to modify the graphs</h3>
From the graph, we have:
and
To derive y < x^2 - 3, we simply change the equality sign in the function f(x) to less than.
To derive y > x^2 + 2, we perform the following transformation on the function g(x)
- Shift the function g(x) down by 2 units
- Reflect across the x-axis
- Shift the function g(x) down by 3 units
- Change the equality sign in the function g(x) to greater than
The inequalities of the graphs become
y < x^2 - 3 and y > x^2 + 2
From the graph of the above inequalities (see attachment), we can see that the curves of the inequalities do not intersect.
Hence, the set of inequalities do not have a solution
Read more about inequalities at:
So, how much acid is there in 6 gallons? well is 20% acid or (20/100), so the amount of acid in it just (20/100) * 6 or 1.2, the rest is say water.
now, if we want a 90% solution, and say we add "y" gallons, how much acid is in it? well (90/100) * y, or 0.9y.
now let's add "x" gallons of pure acid, now, pure acid is just pure acid, so is 100% acid, how much acid is there in it? (100/100) * x, or 1x or just x.
we know whatever "x" and "y" amounts are, they -> x + 6 = y
and we also know that x + 1.2 = 0.9y
now, if we want a 90% solution, and say we add "y" gallons, how much acid is in it? well (90/100) * y, or 0.9y.
now let's add "x" gallons of pure acid, now, pure acid is just pure acid, so is 100% acid, how much acid is there in it? (100/100) * x, or 1x or just x.
we know whatever "x" and "y" amounts are, they -> x + 6 = y
and we also know that x + 1.2 = 0.9y