Janae and Jerome each have m marbles. Gwen has 4(m + 2) marbles. John has 8m + 4 marbles. If John has more marbles than Janae, J erome, and Gwen combined, how many marbles might Janae and Jerome each have? Select each possible answer. A. Janae and Jerome each have 1 marble. B. Janae and Jerome each have 2 marbles. C. Janae and Jerome each have 3 marbles. D. Janae and Jerome each have 4 marbles. E. Janae and Jerome each have 5 marbles.
1 answer:
Answer:
C, D, E
Step-by-step explanation:
The numbers of marbles are:
Janae - m; Jerome - m; Gwen - 4(m+2); John - 8m+4. Janae, Jerome, and Gwen combined have
m + m + 4(m+2) = m + m +4m + 8 =6m + 8 marbles.
If John has more marbles than Janae, Jerome, and Gwen combined, then
So, possible answers are
Janae and Jerome each have 3 marbles; Janae and Jerome each have 4 marbles; Janae and Jerome each have 5 marbles.
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