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gizmo_the_mogwai [7]
3 years ago
10

Translate the following into an algebraic expression:

Mathematics
1 answer:
Nata [24]3 years ago
3 0

For this case, the first thing we must do is define variables.

We have then:

x: number of minutes

y: total cost

We write the algebraic expression that models the problem.

We have then:

y = 10 * (\frac{20}{60}) x

Simplifying we have:

y = (\frac{10}{3}) x

Then, by the time the cost is equal to $ 300 we have:

300 = (\frac{10}{3}) x

From here, we clear the value of x.

Answer:

an algebraic expression for the problem is:

300 = (\frac{10}{3}) x

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Look at the attachment for the work.

3 0
3 years ago
Write the phrase as an expression. Then evaluate the expression when x = 5.
Nadusha1986 [10]

Answer:

6 + 8x

46

Step-by-step explanation:

1. Write the expression

6 + 8x

2. Plug in 5 for x

6 + 8(5) → 6 + 40 = 46

6 0
3 years ago
What is (2+y)³ written out?
Aleksandr-060686 [28]
{ \left( 2+y \right)  }^{ 3 }\\ \\ =\left( 2+y \right) \left( 2+y \right) \left( 2+y \right) \\ \\ =\left( 2+y \right) \left( 4+4y+{ y }^{ 2 } \right)

\\ \\ =2\left( 4+4y+{ y }^{ 2 } \right) +y\left( 4+4y+{ y }^{ 2 } \right) \\ \\ =8+8y+2{ y }^{ 2 }+4y+4{ y }^{ 2 }+{ y }^{ 3 }\\ \\ ={ y }^{ 3 }+6{ y }^{ 2 }+12y+8
5 0
3 years ago
Jeremiah Holmes
olga nikolaevna [1]

Answer:

- 508

Step-by-step explanation:

The n th term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = - 28 and d = - 34 - (- 28) = - 34 + 28 = - 6, thus

a_{81} = - 28 + (- 6 × 80) = - 28 - 480 = - 508

6 0
3 years ago
∣x∣=−5<br> find an absoulute value
kati45 [8]

Answer:

5

Step-by-step explanatio

8 0
3 years ago
Read 2 more answers
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