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Alexeev081 [22]
3 years ago
15

126.4% of what number is 158?

Mathematics
1 answer:
Maksim231197 [3]3 years ago
6 0
<span>126.4% of 158 = 199.712</span>
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Find the 63rd term of the arithmetic sequence -1, 5, 11, ...−1,5,11,...
Ugo [173]

Answer:

a_6_3=371

Step-by-step explanation:

we know that

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant and this constant is called the common difference

we have

-1,5,11,...

Let

a_1=-1\\a_2=5\\a_3=11

a_2-a_1=5-(-1)=5+1=6

a_3-a_2=11-5=6

The common difference is d=6

We can write an Arithmetic Sequence as a rule

a_n=a_1+d(n-1)

where

a_n is the nth term                

d is the common difference

a_1 is the first term

n is the number of terms

Find the 63rd term of the arithmetic sequence

we have

n=63\\d=6\\a_1=-1

substitute

a_6_3=-1+6(63-1)

a_6_3=-1+6(62)

a_6_3=-1+372

a_6_3=371

6 0
4 years ago
What value should be added to both sides for completing the square in this equation?
Mila [183]

Hey there!

x^2 + 4x = 12

SUBTRACT 12 to BOTH SIDES

x^2 + 4x - 12 = 12 - 12

SIMPLIFY IT

x^2 + 4x - 12 = 0

FACTOR the LEFT SIDE of your EQUATION

(x - 2)(x + 6) = 0

• EQUATION #1: x - 2 = 0

OR

• EQUATION #2: x + 6 = 0

SIMPLIFY IT

• EQUATION #1 answer: x = 2

OR

• EQUATION #2 answer: x = -6

OVERALL ANSWER: x = 2 or x = -6

YOUR ANSWER: x = 2 (Option A.)

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

3 0
2 years ago
What is the lateral surface area of this rectangular prism in square centimeters
vlabodo [156]

Answer:

give me sec waitttttttt give me sec is their any answer choice

3 0
3 years ago
You invested money in a fund and each month you receive a payment for your investment. Over the first four months, you received
Alexus [3.1K]

Money received in tenth month: $104

Difference between explicit formula and a recursive formula is: the use of (n-1)th term, nth term and the common difference (d) brings a great difference between the two formulae of an arithmetic progression.

<h3>What is arithmetic progression?</h3>

A series of numbers called an arithmetic progression or arithmetic sequence (AP) has a constant difference between the terms.

Given:

  • Money received in first four months: $50, $52, $55, %59.

To find: Money received in tenth month.

Finding:

As we can see, the pattern followed here is: increment in each amount received each month by $1. Thus it is an arithmetic progression.

That is: 50, 52 (0+2), 55 (2+3), 59 (2 + 3 + 4) and so on.

Thus, for the tenth month, we can use the formula of recursion, given by: a_n=a_{n-1}+n, n ≥ 1.

For a₁ = 50, a₂ = a₁ + 2

=> a₂ = 50 + 2

This way, a₅ = a₄ + 5

=> a₅ = 59 + 5 = 64

a₆ = a₅ + 6

=> a₆ = 64 + 6 = 70

a₇ = a₆ + 7

=> a₇ = 70 + 7 = 77

a₈ = a₇ + 8

=> a₈ = 77 + 8 = 85

a₉ = a₈ + 9

=> a₉ = 85 + 9 = 94

a₁₀ = a₉ + 10

=> a₁₀ = 94 + 10 = 104

Thus, the payment received in tenth month will be $104.

(b) Difference between explicit formula and recursive formula of an arithmetic progression:

  • The first term of a recursive formula is a₁ and the formula for the nth term uses the first term and the common difference, d. One example of a recursive formula is a_n=a_{n-1}+d.
  • A formula for the nth term in an explicit formula would include the initial term a₁, the common difference d, and the term number, n. The equation a_n = a_1 + (n-1)d.

To learn more about arithmetic Progressions, refer to the link: brainly.com/question/6561461

#SPJ4

6 0
1 year ago
Graph the image of the given triangle after the transformation with the rule (x, y)→(x−6, y−4) .
zaharov [31]

Answer: See the figure attached.

Step-by-step explanation:

Observe the figure attached. The vertices of the triangle ABC have the following coordinates:

A(2,5); B(6,2) and C(3,-5)

To graph the image (in this case we can identify it as A'B'C'), you must use the rule (x,y)→(x-6,y-4).

Then, you have to subtract 6 units from the x-coordinate of each vertex and subtract 4 units from the y-coordinate of each vertex.

Therefore, you get:

Vertex A'→ (2-6,5-4)=(-4,1)

Vertex B'→ (6-6,2-4)=(0,-2)

Vertex C'→ (3-6,-5-4)=(-3,-9)

Having the vertices of the image A'B'C', you can graph it (See the figure attached).

7 0
4 years ago
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