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g100num [7]
3 years ago
8

What is 1748/19 simplified

Mathematics
1 answer:
kvasek [131]3 years ago
7 0

Answer:

92

Step-by-step explanation:

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In a village, there are houses, flats and bungalows in the ratio
Elden [556K]

Answer:

270

Step-by-step explanation:

Given that :

Ratio = 14:8:5

Houses : flats : bungalow

Number of bungalow = 50

Sum of ratio = (14 + 8 + 5) = 27

Let total number of households = x

Bungalow = 5/27 * x

5/27 * x = 50

5x / 27 = 50

5x = 50 * 27

5x = 1350

x = 1350 / 5

x = 270

Number of places to live = 270

3 0
3 years ago
From 24 teachers to 30 teachers Find each percent increase. Round to the nearest percent
yulyashka [42]
% = (Change/Original) * 100
= (6/24) * 100
= (0.25) * 100
= 25%
5 0
3 years ago
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A tank contains 1080 L of pure water. Solution that contains 0.07 kg of sugar per liter enters the tank at the rate 7 L/min, and
allsm [11]

(a) Let A(t) denote the amount of sugar in the tank at time t. The tank starts with only pure water, so \boxed{A(0)=0}.

(b) Sugar flows in at a rate of

(0.07 kg/L) * (7 L/min) = 0.49 kg/min = 49/100 kg/min

and flows out at a rate of

(<em>A(t)</em>/1080 kg/L) * (7 L/min) = 7<em>A(t)</em>/1080 kg/min

so that the net rate of change of A(t) is governed by the ODE,

\dfrac{\mathrm dA(t)}[\mathrm dt}=\dfrac{49}{100}-\dfrac{7A(t)}{1080}

or

A'(t)+\dfrac7{1080}A(t)=\dfrac{49}{100}

Multiply both sides by the integrating factor e^{7t/1080} to condense the left side into the derivative of a product:

e^{\frac{7t}{1080}}A'(t)+\dfrac7{1080}e^{\frac{7t}{1080}}A(t)=\dfrac{49}{100}e^{\frac{7t}{1080}}

\left(e^{\frac{7t}{1080}}A(t)\right)'=\dfrac{49}{100}e^{\frac{7t}{1080}}

Integrate both sides:

e^{\frac{7t}{1080}}A(t)=\displaystyle\frac{49}{100}\int e^{\frac{7t}{1080}}\,\mathrm dt

e^{\frac{7t}{1080}}A(t)=\dfrac{378}5e^{\frac{7t}{1080}}+C

Solve for A(t):

A(t)=\dfrac{378}5+Ce^{-\frac{7t}{1080}}

Given that A(0)=0, we find

0=\dfrac{378}5+C\implies C=-\dfrac{378}5

so that the amount of sugar at any time t is

\boxed{A(t)=\dfrac{378}5\left(1-e^{-\frac{7t}{1080}}\right)}

(c) As t\to\infty, the exponential term converges to 0 and we're left with

\displaystyle\lim_{t\to\infty}A(t)=\frac{378}5

or 75.6 kg of sugar.

7 0
3 years ago
What is postulate in geometry
Tatiana [17]
A statement also know as an axiom which is taken to be true without proof.
4 0
3 years ago
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What is the answer? The holidays began at 19 July 2019 and ends at 3 September 2019
Bond [772]

Answer:

114 Oranges

Step-by-step explanation:

Days with t are: Tuesday, Thursday and Saturday.In the period of time given there are 20 T days (20 x 3 = 60 oranges)

In the period of time given there are 27  no T days (27 x 2 = 54 oranges)

60 + 54 = 114 Oranges eaten over the school holidays

7 0
4 years ago
Read 2 more answers
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