What value of m makes the system of linear equations mx − y + 3 = 0, (2m − 1)x − y + 4 = 0 have no solution?
1 answer:
Answer:
m ≠1 ( all m in R except 1 )
Step-by-step explanation:
hello :
mx − y + 3 = 0.....(*)
(2m − 1)x − y + 4 = 0 ....(**)
multiply (*) by : -1 you have : -mx+y-3=0 ....(***)
(2m − 1)x − y + 4 = 0 ....(**)
add(***) and(**) : -mx+ (2m − 1)x+1 =0
(2m-m-1)x+1=0
(m-1)x = -1
this system have no solution if : m-1≠0 means : m ≠1
You might be interested in
=>
The only values a cosine can have are from -1 to 1.
Answer:
volume=0.000064
mass=0.5888kg
Step-by-step explanation:
Answer: Unit rates are the factor that takes you from one column to the other column in a table of equivalent ratios. Equivalent ratios have the same unit rates.
Hope this helps!
