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Annette [7]
3 years ago
11

What value of m makes the system of linear equations mx − y + 3 = 0, (2m − 1)x − y + 4 = 0 have no solution?

Mathematics
1 answer:
Morgarella [4.7K]3 years ago
6 0

Answer:

m ≠1  ( all m in R  except 1 )

Step-by-step explanation:

hello :

mx − y + 3 = 0.....(*)

(2m − 1)x − y + 4 = 0 ....(**)

multiply (*) by : -1       you have :   -mx+y-3=0   ....(***)

                                                    (2m − 1)x − y + 4 = 0 ....(**)

add(***) and(**)  : -mx+ (2m − 1)x+1 =0

(2m-m-1)x+1=0

(m-1)x = -1

this system have no solution  if : m-1≠0   means : m ≠1

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230,464

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Step-by-step explanation: Hope this helped you!

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2 years ago
(18) In the right triangle CDE, Angle E
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3 years ago
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What is the sum of the complex number 2+3i and 4+8i, where i=√-1?
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3 0
3 years ago
2 3/4 - 1 1/8=?
Airida [17]
Basically you need to make the denominator (whats on the bottom) the same, lets take the first one for example


2 3/4, lets put this all over 4 for the same denominator.

2=8/4, and then add this to 3/4 to get 11/4.

the second part will work the same way,

start by making 1 into 8/8. add this to 1/8 to get 9/8


now we have to add 11/4 and 9/8. to do this, you have to find the smallest multiple between the two (for example: between 6 and 4 it would be 12, since 4*3= 12, and 2*6=12)

now, the smallest common multiple between 4 and 8 would just be 8


11/4= 22/8, since you multiply the bottom and top by the same amount so it still equals 11/4, but your denominator will now be 8.


now you can subtract. 22/8- 9/8= 13/8


final answer: 13/8


try the rest yourself since this is important for later math, hoped this helped :)


3 0
2 years ago
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