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stepladder [879]

3 years ago

11

Who is sohcahtoa joe from Csi: Geometry Trig

1 answer:

inna [77]3 years ago

8 0

SOH CAH TOA is the acronym to help students, like you, understand and remember how to calculate <span>the sine, cosine, and tangent of an angle.

S - sine = Opposite over Hypotenuse
C - cosine = Adjacent over Hypotenuse
T - tangent = Opposite over Adjacent</span>

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Find two numbers that multiply to -72 and add up to -1

Andrews [41]

Answer:

-8 and 9

Step-by-step explanation:

-8 x 9 = -72

and -8 + 9 = 1

7 0

3 years ago

2x^2+5x+3/x^2-3x-4 divided by 4x^2+2x-6/x^2-8x+16

Masja [62]

Answer: $\frac{x-4}{2x-2}$

Step-by-step explanation:

$\frac{2x^2+5x+3}{x^2-3x-4}$ divided by $\frac{4x^2+2x-6}{x^2-8x+16}$ is the same thing as multiplying $\frac{2x^2+5x+3}{x^2-3x-4}$ by $\frac{x^2-8x+16}{4x^2+2x-6}$ .

The equation we get is:

$\frac{2x^2+5x+3}{x^2-3x-4}*\frac{x^2-8x+16}{4x^2+2x-6}$

With this equation, we can factor each equation:

$\frac{(x+1)(2x+3)}{(x+1)(x-4)} *\frac{(x-4)(x-4)}{2(x-1)(2x+3)}$

We can cancel out like terms since they would be dividing each other:

$\frac{x-4}{2x-2}$

8 0

3 years ago

CAN SOMEONE HELP ME!<br>

Georgia [21]

Answer:

26

Step-by-step explanation:

5 × 4 = 20 (rectangle)

8-5 = 3 (triangle)

3×4÷2 = 6

20+6 = 26

4 0

3 years ago

Calculate the resistance of a 270-cm length of copper wire with a 0.030-cm2 cross-sectional area. ( = 1.8 · 10-6 ohm-cm) R = ___

devlian [24]

Answer:

Given:-

The length of copper wire (L) = 270 cm

Area of cross-sectional (A) = 0.030 $cm^2$

and specific resistance (ρ) = $1.8 \times 10^{-6}$ ohm-cm.

Use the formula R=(Specific resistance*L)/A, to calculate the Resistance(R)

then, $R=\frac{1.8 \times 10^{-6} \times 270}{0.030}$ ohm

Simplify:

R = 0.0162 ohm = $1.62\times 10^{-2}$ ohm

Therefore, the resistance of copper wire is, $1.62\times 10^{-2}$ Ω

8 0

3 years ago

draw a model to represent the problem. 2/3 divided into 1/3 size pieces. how many 1/3 pieces will be in 2/3?

Hunter-Best [27]

That shows the answer of how to do it

6 0

3 years ago