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BARSIC [14]
3 years ago
14

Which equation can be used to find the measure of angle BAC? A.) inverse tan (5/12) B.) inverse cos (5/13) C.) inverse sin (12/5

) D.) inverse tan (12/13)

Mathematics
1 answer:
finlep [7]3 years ago
5 0

Answer:

B

Step-by-step explanation:

The angle that has tan 5 / 12 is ∠ABC so A is not the answer. The angle that has cos 5 / 13 is ∠BAC so B is the answer.

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-3z-11=11z^2

Step-by-step explanation:

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1 year ago
Solve for x.<br> 163 - x= -52<br> O A r = -215<br> B. X=-111<br> C. x = 111<br> D. x = 215
Eduardwww [97]

Answer:

D

Step-by-step explanation:

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3 years ago
N a? triangle, the measure of the first angle is twicetwice the measure of the second angle. the measure of the third angle is 1
Mrac [35]
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3 years ago
PLEASE HELP <br>If BC DA, then which segment is the shortest side?​
NeX [460]

The length of the shortest side is DC

<h3>How to determine the shortest side?</h3>

As a general rule in triangle;

The smallest angle in a triangle is opposite the shortest side.

Similarly, the largest angle in a triangle is opposite the largest side.

From the given figure of triangles, the smallest angle is angle CBD with a measure of 47 degrees.

The side opposite this angle is side length DC

Hence, the length of the shortest side is DC

Read more about triangles at:

brainly.com/question/21735282

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5 0
2 years ago
Complete the given diagram by dragging expressions to each leg of the triangle. Then, correctly complete the equation to derive
Nimfa-mama [501]

The equation to derive the distance d is \sqrt{(x2-x1)^2+(y2-y1)^2}. The lengths of the other legs of the given triangle are (y2 - y1) and (x2 - x1).

<h3>What is the formula for calculating the distance between two points?</h3>

Consider the two points (x1, y1) and (x2, y2)

The formula used for calculating the distance between the two points is

distance = \sqrt{(x2-x1)^2+(y2-y1)^2}

<h3>Calculation:</h3>

Given that,

The triangle in the graph has vertices (x1, y1), (x2, y2), and (x2, y1)

Since this triangle makes 90°, it is a right-angled triangle.

Hypotenuse = (x1, y1) to (x2, y2), Adjacent = (x1, y1) to (x2,y1), and Opposite = (x2, y1) to (x2, y2).

Consider the length of the hypotenuse = d

So, using the distance formula, the length of the hypotenuse(d) is,

d = \sqrt{(x2-x1)^2+(y2-y1)^2}

And the lengths of the other two legs of the given triangle are,

Length of the adjacent side: (x1, y1) to (x2,y1)

= \sqrt{(x2-x1)^2+(y1-y1)^2}

= \sqrt{(x2-x1)^2+0}

= (x2-x1)

Length of the opposite side: (x2, y1) to (x2, y2)

= \sqrt{(x2-x2)^2+(y2-y1)^2}

= \sqrt{0+(y2-y1)^2}

= (y2-y1)

Therefore, the derived distances for the given triangle are:

d=\sqrt{(x2-x1)^2+(y2-y1)^2}, (x2 - x1), and (y2 - y1).

Learn more about the distance between two points here:

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4 0
1 year ago
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