Question

Company earns S dollars by selling y items per week. According to the equation S(y)=−2y^2+60y+10, how many items does company need to sell to maximize earnings.

Answer 1

Answer:

$Max = 15$

Step-by-step explanation:

Given

$s(y) = -2y^2 + 60y + 10$

Required

Determine number of items that gives maximum earnings;

The general form of a quadratic equation is:

$s(y) = ay^2 + by + c$

And the maximum is calculated as:

$Max = \frac{-b}{2a}$ If a<0

Comparing $s(y) = ay^2 + by + c$ to $s(y) = -2y^2 + 60y + 10$

We have that:

$a = -2$     $b = 60$   $c = 10$

Substitute these values to

$Max = \frac{-b}{2a}$

$Max = \frac{-60}{2 * -2}$

$Max = \frac{-60}{-4}$

$Max = 15$

The number of item that maximizes the function is when y = 15