Using the triangle of pascal we have that the expression equivalent to (x + y) ^ 6 is given by:
x ^ 6 + 6x ^ 5y + 15x ^ 4y ^ 2 + 20x ^ 3y ^ 3 + 15x ^ 2y ^ 4 + 6xy ^ 5 + y ^ 6
Therefore, the coefficients of the expansion are given by:
1, 6, 15, 20, 15, 6, 1
Answer:
The coefficients corresponding to k = 0, 1, 2, ..., 6 in the expansion of (x + y) ^ 6 are 1, 6, 15, 20, 15, 6, 1
Answer:
x=0 x=2
Step-by-step explanation:
X² - 2x=0
Factor
x(x-2) = 0
Using the zero product property
x=0 x-2 =0
x=0 x=2
Answer:
<h3> f^−1(x) = x + 7</h3>
Step-by-step explanation:
Replace f(x) with y. y = x − 7
Interchange the variables. x = y − 7
Solve for y. y = x + 7
Solve for y and replace with f^−1 (x). f^−1(x) = x + 7
I hope this helps have a great day :)
Remember that things like this, always need to add up to 180°.
Y = 44
180 - 88 = 92
180 - 92 = 88
88/2 = 44
