The sum of partial product is not always equal to a final product
The value of the angles should be. (x-40°). , (x-20°), (½x-10°) , not (x-40°) + (x-20°)+(½x-10°)
Sum of all the interior angles of a triangle is 180°.
So a equation can be made by the given data,
(x-40°) + (x-20°) + (½ x-10°) = 180°
x-40°+x-20°+½x-10° = 180°
2x+½x -60°-10° = 180°
5/2 x - 70° = 180°
5/2 x = 180° + 70°
5/2 x = 250°
x = 250° × 2/5
x = 50° × 2
x = 100°
So the angles are
x-40° = 100°-40° = 60°
x-20° = 100°–20° = 80°
½x-10° = ½(100)° - 10° = 50° -10° = 40°
The answer can be checked by putting the values of the angle we got in the second statement i.e. Sum of all the interior angles of a triangle is 180°.
60° + 80° + 40° = 100° + 80° = 180°
Is there a graph for this problem?
The right answer is Option A.
Step-by-step explanation:
Let,
x be the postcards
y be the large envelops
According to given statement;
14x+5y=12 Eqn 1
10x+15y=24.80 Eqn 2
Multiplying Eqn 1 by 3;

Subtracting Eqn 2 from Eqn 3;

Dividing both sides by 32

Putting x=0.35 in Eqn 1;

Dividing both sides by 5

Therefore, one large envelope costs $1.42
The right answer is Option A.
Keywords: linear equations, subtraction
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Answer:
Given:
and
.
Prove: 
Since
, By the definition of perpendicular lines angles 1, 2, 3 and 4 are 90 degree. similarly
, it means angles 5, 6, 7 and 8 are 90 degree.
We can say that,
,
,
and 
From figure it is noticed that the angle 1 and 5 are corresponding angles.
If two parallel lines are intersected by a transversal, then the corresponding angles are equal.
Since corresponding angles are congruent, therefore the line must be parallel to each other.
Hence proved that
.