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Goryan [66]
3 years ago
10

Solve the equation 3cosx = 5sinx for x in the interval 0 smaller than equal to x smaller than equal to 360 degrees.

Mathematics
1 answer:
Artist 52 [7]3 years ago
5 0
The equation is false, because 3 \neq <span>4.794579</span>
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Jon has two trees in his yard. One is 29 feet taller than the other. If we let h be the height of the shorter tree, write an alg
inessss [21]

h + h + 29

This will be simplified into 2h + 29

The shorter tree's height is represented with the variable 'h'

Because the taller tree is 29 feet taller, the equation for the taller tree would be 'h + 29'

SInce we're looking for the sum, all you have to do is add 'h' and 'h + 29'

If you have any questions, just ask. Good luck! :))

-T.B.

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3 years ago
9 Calculator What is the median of the data set? 3, 10, 1, 6, 10, 3, 11, 14<br><br><br><br><br>​
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Answer:

1, 3, 3, 6, 10, 10, 11, 14

(6,10)  6+10= 16  

16/2= 8

median is = 8

Step-by-step explanation:

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3 years ago
What is the LCD of 3/10 and -4/15??
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The LCD is 30.  The fractions would be 9/30 and -8/30
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3 years ago
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Graph the ordered pairs for y = 4x + 2 <br> using {-2,1,2}
deff fn [24]
No clue there has to be a graph paper for the answer
3 0
3 years ago
The volume of a rectangular box with a square base remains constant at 500 cm3 as the area of the base increases at a rate of 6
Andre45 [30]

Answer:

the rate at which the height of the box is decreasing is -0.0593 cm/s

Step-by-step explanation:

Given the data in the question;

Constant Volume of a rectangular box with a square base = 500 cm³

area of the base increases at a rate of 6 cm²/sec

so change in the area of the base with respect to time dA/dt = 6 cm²/sec

each side of the base is 15 cm long

so Area of the base = 15 cm × 15 cm = 225 cm²

the rate at which the height of the box is decreasing = ?

Now,

V = Ah

dv/dt = 0 ⇒ Adh/dt + hdA/DT = 0

⇒ dh/dt = -hdA/dt / A

we substitute

dh/dt = [ -( 500 / 225 ) × 6 ] / 225

dh/dt = [ -(2.22222 × 6)  ] / 225

dh/dt = [ -13.3333 ] / 225

dh/dt = -0.0593 cm/s

Therefore, the rate at which the height of the box is decreasing is -0.0593 cm/s

7 0
3 years ago
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