Let the positive odd numbers be x,x+2,x+4.
According to the question,
5(3x+30)=72+x^2+4x
x^2-13x+42=0
(x-6) and (x-7)=0
x=6 or x=7
Answer:
See the attached graph from which we obtain x = 3 as the only solution for the given equation.
Step-by-step explanation:
Notice that the equation is the same equation as when y = 0 in the function , since when y=0 we have:
Then what we need to find is for which values of "x" in the graph of y = x^2-6x+9, the graph touches or crosses the x-axis (that is when y=0)
We graph the given function in the x-y coordinate system and find where it renders zero for "y" (see attached graph).
We see that there is only one point of contact with the x-axis at x = 3
the correct answer is 124
Answer:
concave pentagon
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
1st year-> 30000
2nd year-> 31800
3rd year ->33708
4th year->35730.48
5th year -> 37874.3088
37874.3088+35730.48+33708+31800+30000= 169112.7888
≈ 169113