If you understand what is linear pair, you can see the same in triangle also. A linear pair is a pair of adjacent, supplementary angles. Adjacentmeans next to each other, and supplementary means that the measures of the two angles add up to equal 180 degrees.
Answer:
B. y = 1/3x
Step-by-step explanation:
The slope of the given line is -3, so the slope of the perpendicular line will be the negative reciprocal of that: -1/(-3) = 1/3. This eliminates choices A and C.
We can find the y-intercept (b) if we use the given point values in the equation ...
y = 1/3x +b
we get ...
-2 = (1/3)(-6) +b
-2 = -2 +b . . . simplify
0 = b . . . . . . . add 2
So, the equation of the perpendicular line through the given point is ...
y = 1/3x . . . . matches choice B
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<em>Alternate solution method</em>
You can try the given point in the given equations. You will find that only the equation of choice B will work.
Part A;
There are many system of inequalities that can be created such that only contain points C and F in the overlapping shaded regions.
Any system of inequalities which is satisfied by (2, 2) and (3, 4) but is not stisfied by <span>(-3, -4), (-4, 3), (1, -2) and (5, -4) can serve.
An example of such system of equation is
x > 0
y > 0
The system of equation above represent all the points in the first quadrant of the coordinate system.
The area above the x-axis and to the right of the y-axis is shaded.
Part 2:
It can be verified that points C and F are solutions to the system of inequalities above by substituting the coordinates of points C and F into the system of equations and see whether they are true.
Substituting C(2, 2) into the system we have:
2 > 0
2 > 0
as can be seen the two inequalities above are true, hence point C is a solution to the set of inequalities.
Part C:
Given that </span><span>Natalie
can only attend a school in her designated zone and that Natalie's zone is
defined by y < −2x + 2.
To identify the schools that
Natalie is allowed to attend, we substitute the coordinates of the points A to F into the inequality defining Natalie's zone.
For point A(-3, -4): -4 < -2(-3) + 2; -4 < 6 + 2; -4 < 8 which is true
For point B(-4, 3): 3 < -2(-4) + 2; 3 < 8 + 2; 3 < 10 which is true
For point C(2, 2): 2 < -2(2) + 2; 2 < -4 + 2; 2 < -2 which is false
For point D(1, -2): -2 < -2(1) + 2; -2 < -2 + 2; -2 < 0 which is true
For point E(5, -4): -4 < -2(5) + 2; -4 < -10 + 2; -4 < -8 which is false
For point F(3, 4): 4 < -2(3) + 2; 4 < -6 + 2; 4 < -4 which is false
Therefore, the schools that Natalie is allowed to attend are the schools at point A, B and D.
</span>
Answer:
I think 3 ............................three
In commission he made $30, and in all he made 780$
