263.27 m^2
rectangle : 15 x 10 = 150 m^2
the half circle at the top has a diameter of 6m. therefore, it’s radius is 3m. if it is cut in half, the part removed from the triangle height is 3m. therefore, the height of the triangle is 35 -15 = 20; 20 - 3 = 17. the height of the triangle is 17. the triangle area formula is a = 1/2(bh).
a = 1/2 (10)(17)
a = 1/2 (170)
a = 85 m^2
the circle would be a = πr^2 but divided by 2 bc it’s a half circle
a = π(3)^2
a = π9
a = 28.27 m^2
150 + 85 + 28.27 = 263.27 m^2
Y-intercept: Let x = 0. Result: 5x=0, and x= 0. y-intercept is (0,0).
Similarly, x-int. is (0,0) (after going thru the same procedure: set y=0 and find x)
Answer:
6
Step-by-step explanation:
Perimeter = 2l + 2w
48 = 2(18) + 2(w)
48 = 36 + 2w
12 = 2w
w = 6
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Answer:
Step-by-step explanation:
Given a general quadratic formula given as ax²bx+c = 0
To generate the general formula to solve the quadratic equation, we can use the completing the square method as shown;
Step 1:
Bringing c to the other side
ax²+bx = -c
Dividing through by coefficient of x² which is 'a' will give:
x²+(b/a)x = -c/a
- Completing the square at the left hand side of the equation by adding the square of half the coefficient x i.e (b/2a)² and adding it to both sides of the equation we have:
x²+(b/a)x+(b/2a)² = -c/a+(b/2a)²
(x+b/2a)² = -c/a+(b/2a)²
(x+b/2a)² = -c/a + b²/4a²
- Taking the square root of both sides
√(x+b/2a)² = ±√-c/a + b²/√4a²
x+b/2a = ±√(-4ac+b²)/√4a²
x+b/2a =±√b²-4ac/2a
- Taking b/2a to the other side
x = -b/2a±√√b²-4ac/2a
Taking the LCM:
x = {-b±√b²-4ac}/2a
This gives the vertex form with how it is used to Solve a quadratic equation.
Answer:
See Explanation
Step-by-step explanation:
Line l is bisector of MO... (given)
![\therefore NO + NO = MO..[From \:(1)]](https://tex.z-dn.net/?f=%20%5Ctherefore%20NO%20%2B%20NO%20%3D%20MO..%5BFrom%20%5C%3A%281%29%5D%20)
Thus Proved
