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Elina [12.6K]
3 years ago
6

10. In rolling 3 dice, are the events A: Sum divisible by 3 and B: Sum divisible by 5 mutually exclusive?

Mathematics
1 answer:
dalvyx [7]3 years ago
6 0

Answer: No, the events A and B are not mutually exclusive.

Step-by-step explanation:

We say any two events P and Q are mutually exclusive , if they are disjoint set such that their intersection is empty.

Given : In rolling 3 dice, we have two events

Event A: Sum divisible by 3

Event B: Sum divisible by 5

But the sum of all 3 dices can 15 and 15 is divisible by 3 and 5.

The intersection of events A and B have = {(5,5,5), (3,6,6), (6,3,6), (6,6,3),(5,4,6), (6,4,5), (4,6,5), (4,5,6), (6,5,4), (5,6,4)}

Hence, the events A and B are not mutually exclusive.

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The price of Stock A at 9 A.M. Was ​$12.53. Since​ then, the price has been increasing at the rate of ​$0.12 each hour. At noon
Vinvika [58]

Answer:

1.8571428 hours

Step-by-step explanation:

Given that :

Price of stock A at 9 am = $12.53

Rate of increase = $0.12 per hour

Price of stock B at noon = $13.28

Rate of Decrease = $0.09 per hour

Let number of hours = x

Price of stock A at noon :12.53 + 0.12(3) = 12.89

12.89 + 0.12x = 13.28 - 0.09x

0.12x + 0.09x = 13.28 - 12.89

0.21x = 0.39

x = 0.39 / 0.21

x = 1.8571428

Hence the prices of the stock will be the at about 1.857 hours

6 0
3 years ago
What are the length of each side of a quadrilateral when the perimeter is 33 and the sides are:
solong [7]
Answer: 
A = 6 
So 
Side A = 6 
Side B = 11 
Side C = 3 
Side D = 13

Explanation: 
To solve perimeter of a quadrilateral, you use this formula: 
side A + side B + side C + side D = total perimeter.

If the four sides are A, A + 5, A – 3, and 2A + 1 then you need to solve for A.

Write out an algebraic formula with these values:
A + (A + 5) + (A – 3) + (2A + 1) = P 
You also know that the total perimeter is 33, so :
A + (A + 5) + (A – 3) + (2A + 1) = 33 
You can add all the A values together to combine like terms like this:
5A + 5 – 3 + 1 = 33 
Solve fore A:
5A + 3 = 33 
5A = 33 – 3 
5A = 30 
A = 30 ÷ 5 
A = 6 

Check your answer: 
A + (A + 5) + (A – 3) + (2A + 1) = 33 
(6) + ((6) + 5) + ((6) – 3) + (2(6) + 1) = 33 
(6) + (11) + (3) + (13) = 33 
17 + 16 = 33 
33 = 33 

4 0
4 years ago
What is the answer for <br><br> -5 1/5 - 2 3/10
Fofino [41]

Answer:

-7.5 also as -7 1/2

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
At an airport, it cost 7 to park for one hour and 5 per hour for each additional hour.Let x represent the number hours parked.wr
kompoz [17]
The cost of parking is an initial cost plus an hourly cost.
The first hour costs $7.
You need a function for the cost of more than 1 hour,
meaning 2, 3, 4, etc. hours.
Each hour after the first hour costs $5.

1 hour: $7
2 hours: $7 + $5                  = 7 + 5 * 1          = 12
3 hours: $7 + $5 + $5          = 7 + 5 * 2          = 17
4 hours: $7 + $5 + $5 + $5  = 7 + 5 * 3          = 22

Notice the pattern above in the middle column.
The number of $5 charges you add is one less than the number of hours.
For 2 hours, you only add one $5 charge.
For 3 hours, you add two $5 charges.

Since the number of hours is x, according to the problem, 1 hour less than the number of hours is x - 1.

The fixed charge is the $7 for the first hour.
Each additional hour is $5, so you multiply 1 less than the number of hours,
x - 1, by 5 and add to 7.

C(x) = 7 + 5(x - 1)

This can be left as it is, or it can be simplified as

C(x) = 7 + 5x - 5

C(x) = 5x + 2

Answer: C(x) = 5x + 2

Check:
For 2 hours: C(2) = 5(2) + 2 = 10 + 2 = 12
For 3 hours: C(3) = 5(3) + 2 = 15 + 2 = 17
For 4 hours: C(3) = 5(4) + 2 = 20 + 2 = 22
Notice that the totals for 2, 3, 4 hours here
are the same as the right column in the table above.
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