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NikAS [45]
3 years ago
14

The area of a square is 64n^36 square units. what is the side length of one side of the square

Mathematics
2 answers:
sesenic [268]3 years ago
8 0
Area = (side length)^2

Here,
 64n^36 = s^2.  Take the sqrt of both sides, obtaining 8n^18 = s.  This is the principal square root.  We use this positive quantity because the measure of side length must be positive.

shutvik [7]3 years ago
4 0

Answer:

The answer is 8n^18

Step-by-step explanation:

I just took the test :)

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3,000 yd3 = 200 dtl
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Select Independent or Not independent for each situation. Not independent Independent a. A jar contains fifteen coins. Two coins
satela [25.4K]

Answer:

The correct answers are a. Independent; b. Independent; c. Independent;  e.  Not Independent

Step-by-step explanation:

a. A jar contains fifteen coins which. Two coins are picked randomly without replacement. Thus the second pick is not dependent on the first pick as the coins in the all same and thus the experiment is independent.

b. A number cube is rolled twice. Outcome of the first roll is independent of the outcome in the second and thus the experiment is independent.

c. A box contains number cards labeled from 1 to 10 where 2 cards are chosen randomly with replacement. Hence first draw does not effect the sample making the experiment independent.

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3 0
3 years ago
There is a bag filled with 5 blue and 6 red marbles.
Afina-wow [57]

Answer:

The probability of getting two of the same color is 61/121 or about 50.41%.

Step-by-step explanation:

The bag is filled with five blue marbles and six red marbles.

And we want to find the probability of getting two of the same color.

If we're getting two of the same color, this means that we are either getting Red - Red or Blue - Blue.

In other words, we can find the independent probability of each case and add the probabilities together*.

The probability of getting a red marble first is:

\displaystyle P\left(\text{Red}\right)=\frac{6}{11}

Since the marble is replaced, the probability of getting another red is: \displaystyle P\left(\text{Red, Red}\right)=\frac{6}{11}\cdot \frac{6}{11}=\frac{36}{121}

The probability of getting a blue marble first is:

\displaystyle P\left(\text{Blue}\right)=\frac{5}{11}

And the probability of getting another blue is:

\displaystyle P\left(\text{Blue, Blue}\right)=\frac{5}{11}\cdot \frac{5}{11}=\frac{25}{121}

So, the probability of getting two of the same color is:

\displaystyle P(\text{Same})=\frac{36}{121}+\frac{25}{121}=\frac{61}{121}\approx50.41\%

*Note:

We can only add the probabilities together because the event is mutually exclusive. That is, a red marble is a red marble and a blue marble is a blue marble: a marble cannot be both red and blue simultaneously.

4 0
2 years ago
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