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Julli [10]
3 years ago
7

20,000 is 1/10 of what?

Mathematics
1 answer:
sdas [7]3 years ago
4 0
I was taught a formula for this in seven grade. 


I set it up like this

20,000/n = 1/10


you use the cross multiply rule. 

so.. 


20,000 × 10 = 200,000


n × 1 = 1n


now your left with 


200,000/1n


200,000 divided by 1 is 200,000 


so n = 200,000

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The two polygons above are similar. The scale factor of the smaller polygon to the larger polygon is 3. The area of the smaller
Softa [21]
You would think it was 3 * 12 = 36. Not so. All polygons have to be broken down into some figure that will give 2 dimensions that are at right angles to each other. That would mean that
d1 * d2 = Area for the small polygon
3d1 * 3d2 = area of the larger polygon

What that means is that the area of the larger one is 9 times the smaller one.
Area large = 12 * 9 = 108 square units. <<<<< answer.

If you find this hard to be leave try it with a square.
Suppose you have a square (the small one) that is 3 cm by 3 cm
The small one has an area of 3*3 cm^2 = 9 cm

Now you have another square that is 3 times larger. That means that each side is 3*3 = 9
So s = 9
Area = s^2
Area = 9^2 = 81 cm^2
81 is 9 times larger than 9 just as you would think. 


4 0
3 years ago
How do I find area of a circle if they only give me the diameter
disa [49]

Answer:

divide the diameter by 2

Step-by-step explanation:

the equation for the area of a circle is Pi times the radius squared. the radius is half the diameter, so if you need to find the area of the circle, just divide the diameter by 2 and you will have the length of the radius. then, jut plug it in to the equation.

7 0
3 years ago
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The area of a right triangle is sixty square centimetres. Its base is one centimetre less than twice its height. If the base and
NemiM [27]

Answer:

5. None of the above

Step-by-step explanation:

We have this information:

A = 60 cm2

b = 2*h - 1

Let's find out b and h:

The equation of the are of a triangle is A = (b*h)/2, if we replace it with our information, we have

60 = ((2*h - 1) * h)/2\\ 120 = 2*h^2 - h\\ 0 = 2*h^2 - h - 120

Let's find h with the quadratic formula:

\fbox {Quadratic formula:}  \frac{-b\pm\sqrt{b^2-4ac}}{2a}

h = \frac{-(-1)\pm\sqrt{(-1)^2-4*2*(-120)}}{2*2} = \frac{1\pm\sqrt{961}}{4} = \frac{1\pm\ 31}{4}

h = 8 or h = -7.5

But h represents the height of the triangle, so it has to be a positive number, that's h = 8.

If we replace this in the equation we had for b, we have that b = 2*8 - 1 = 15.

Now we can calculate the hypotenuse with the Pythagorean equation  

\fbox {Pythagorean equation:} <em>The square of the length of the hypotenuse (the side opposite the right angle) of a right triangle is equal to the sum of the squares of the two legs (the two sides that meet at a right angle). </em>

The base and the height are our legs. We will use "H" for the hypotenuse

H^2 = b^2 + h^2 = 15^2 + 8^2 = 289\\ H = \sqrt {289} = 17

H = 17

If we decrease the base and the height by 2 centimeters, we have  

b' = 15 - 2 = 13 and h' = 8 - 2 = 6

With this, let's calculate the new hypotenuse:

H'^2 = b'^2 + h'^2 = 13^2 + 6^2 = 205\\ H' = \sqrt {205} \approx 14.3

H' \approx 14.3

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3 0
3 years ago
The diagonals of quadrilateral ABCD
kap26 [50]

Answer:

Step-by-step explanation:

16 ae =x

6 0
3 years ago
A point G on a segment on a segment with endpoints F(4, 8) and H(10, 12) partitions the segment in a 3:4 ratio. Find G. You must
Andru [333]

Suppose, we are given

two points as

F as (x1, y1)

H as (x2, y2)

assume  it divides  in m/n

we can use formula

G=(x,y)=(\frac{mx_2+nx_1}{m+n}, \frac{my_2+ny_1}{m+n})

now, we are given points as

F=(x1, y1)=(4,8)

x_1=4,y_1=8

H=(x2, y2)=(10,12)

x_2=10, y_2=12

\frac{m}{n} =\frac{3}{4}

so,

m=3,n=4

now, we can find  

x=(\frac{3*10+4*4}{3+4}, y=\frac{3*12+4*8}{3+4})

x=\frac{46}{7} , y=\frac{68}{7}

so, point is

G=(\frac{46}{7} , \frac{68}{7}).................Answer

7 0
3 years ago
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