Answer:
x=5
Step-by-step explanation:
x +2,2x,2x+3 are in A.P. ⇒(2x)−(x+2)=(2x+3)−(2x) 2x−x−2=2x+3−2x x−2=3 So the answer is: x=5
Answer:
Proved
Step-by-step explanation:
Let a, b be two odd numbers
We know odd numbers give remainder as 1 when divided by 2
Hence a and b can be written as
, for some integers m and n.
Now product
=
We have when m and n are integers, 2mn+m+n also will be an integer say s
Then product
again gives remainder 1 when divided by 2
Hence product is odd.
Answer:
DNE (does not exist)
Step-by-step explanation:
Our function is: . We want to find the limit of this as x approaches 0. The first thing we would want to do is to substitute 0 in for x. But when we do that, we get 0/0, which is undefined:
Let's divide the numerator and denominator both by x:
Now substitute 0 in again:
Because we have a number divided by 0, this cannot exist. If we graph this function (see attachment), we'll also see that the graph diverges at x = 0, so the limit does not exist.
Answer:
Step-by-step explanation:
we have
we know that
In the function
The variable of the function f is now the function g(x)
substitute