Question

If you can solve it.Thanks in advance

Answer 1

Answer:

$f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}$

Step-by-step explanation:

we have

$f(x)=x^{2} +\frac{1}{\sqrt[3]{x}}$

$g(x)=\frac{1}{x^{2}+1}$

we know that

In the function

$f(g(x))$

The variable of the function f is now the function g(x)

substitute

$f(g(x))=(\frac{1}{x^{2}+1})^{2} +\frac{1}{\sqrt[3]{(\frac{1}{x^{2}+1})}}$

$f(g(x))=\frac{1}{(x^{2}+1)^{2}} +\sqrt[3]{x^{2}+1}$