In which quadrant do the points have negative x-coordinates and negative y-coordinates?

2 answers:

7 0

Say we have (-5, -7).

You would go 5 left, and then 7 down. That would land you in Quadrant III.
The top right quadrant is quadrant I, the top left is quadrant II, the bottom left is Q. III, the bottom right is Q. IV.

posledela3 years ago

5 0

The answer is Quadrant III.

You might be interested in

What is the inverse operation of - 8x?

mart [117]

Answer:

Step-by-step explanation:

4 0

3 years ago

The volume of a sphere of its function, v= 4/3 times 3.14 times 11.2 to the third power

pantera1 [17]

Answer:

i guess, you pretty much made a statement not a question.

Step-by-step explanation:

5 0

3 years ago

Basketball shoes are on sale for 22% off. What is the regular price if the sale price is $42?

artcher [175]

Answer:

x =53.85

Step-by-step explanation:

Let x be the original price

If the price is 22% of, you will pay 100% -22% = 78%

x * 78% = 42

Change to decimal form.

78x = 42

Divide each side by .78.

78x/.78 = 42/.78

Rounding to the nearest cent

x =53.85

4 0

3 years ago

Read 2 more answers

Simplify: cos2x-cos4 all over sin2x + sin 4x

GrogVix [38]

Answer:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)$

Step-by-step explanation:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}$

Apply formula:

$\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$ and

$\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$

We get:

$=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}$