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Dafna11 [192]
3 years ago
5

4-[2.5(5.4+2.6)-(-7.2)

Mathematics
1 answer:
valkas [14]3 years ago
7 0
-23.2 I think this is the answer
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Think about a population proportion that you may be interested in and propose a confidence interval problem for this parameter.
o-na [289]

Answer: The confidence interval would be (0.2928,0.3672).

Step-by-step explanation:

Since we have given that

Total number of vehicles = 432

Number of SUVs sold = 142

So, it becomes,

\hat{p}=\dfrac{x}{n}=\dfrac{142}{432}=0.33

At 90% confidence interval,

z = 1.645

So, the confidence interval would be

\hat{p}\pm z\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.33\pm 1.645\sqrt{\dfrac{0.33\times 0.67}{432}}\\\\=0.33\pm 0.0372\\\\=(0.33-0.0372,0.33+0.0372)\\\\=(0.2928,0.3672)

Hence, the confidence interval would be (0.2928,0.3672).

8 0
3 years ago
I need help! I have an idea of which pick.
Goshia [24]

Answer: ok so I am bad at this but i would pick.....the top one

Step-by-step explanation:

4 0
3 years ago
Which item has a unit rate of $6.50?
marshall27 [118]

Answer:

T-shirts

Step-by-step explanation:

First, find the unit price for caps. Divide 25 by 4, which equals $6.25. Then, divide 20.25 by 3, which equals $6.75. Next, divide 30 by 4, which equals $7.50. Finally, divide 32.50 by 5, which equals $6.50. To t-shirts have a unit rate of $6.50

4 0
3 years ago
Read 2 more answers
The result of 2/3 times 18 is?
Otrada [13]
Two-thirds times eighteen is twelve
6 0
3 years ago
Read 2 more answers
1. Four cards are drawn at random without replacement from a standard deck of 52 cards. Compute the probability that all are of
OLga [1]

Answer:

1) 10.55%

2) 30.77%

Step-by-step explanation:

52/52•39/51•26/50•13/49 = 0.105498... ≈ 10.55%

100% chance you draw a unique card on the first draw

51 cards left of which 13(3) = 39 are unique suit for your second draw

50 cards left of which 13(2) = 26 are unique suit for your third draw

49 cards left of which 13(1) = 13 are unique suit for your forth draw.

Two balls are already green

Leaves 4 red balls in a field of 13 balls

4/13 = 0.307692... ≈ 30.77%

3 0
2 years ago
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