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3 years ago

7

How would I solve this?

2 answers:

WINSTONCH [101]3 years ago

6 0

This is the answer ^^

goldenfox [79]3 years ago

3 0

So you can convert them into top heavy fractions 5/2 and 14/3 then you need to make the denominators(the bottom numbers) the same
So they both go into 6
15/6+28/6=43/6 or 7 1/6

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Answer:

<u> $Y=4x^2+3x-6$ </u>

Step-by-step explanation:

For the standard form equation to model the values in the table, each value of x in the table should give the matching the y value when substituted into the equation. We will test each equation:

<u> $Y=3x^2+4x-6$ for (-2,4)</u>

$Y=3(-2)^2+4(-2)-6=3(4)+-8-6=12+-8-6=-2\\$

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<u> $Y=4x^2+3x-6$ for (-2,4)</u>

$Y=4(-2)^2+3(-2)-6=4(4)+-6-6=16+-6-6=-4\\$

This does give 4 as the answer and is a possible solution.

<u> $Y=4x^2-3x-6$ for (-2,4)</u>

$Y=4(-2)^2-3(-2)-6=4(4)+6-6=16+6-6=16\\$

This does not give 4 as the answer and is not a solution.

<u> $Y=-4x^2-3x-6$ for (-2,4)</u>

$Y=-4(-2)^2-3(-2)-6=-4(4)+6-6=-16+6-6=-16\\$

This does not give 4 as the answer and is not a solution.

The only possible solution is <u> $Y=4x^2+3x-6$ </u>

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