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4 years ago

X^3 = 125 x = ? Help!!!!

Mathematics

2 answers:

velikii [3]4 years ago

4 0

The answer is 5. 5 x 5= 25 x 5= 125

Andrei [34K]4 years ago

3 0

Answer is 5 hope it helps

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What percent is 11÷88

omeli [17]

Answer:

hello

Step-by-step explanation:

it must be 0,125

hope it helps

4 0

3 years ago

Read 2 more answers

B. Determine the values of a and b so that f is continuous.<br><br> Please help!

wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

So,

$\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3$

$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$

So, the value of $a \ and \ b= \frac{1}{2}$

4 0

3 years ago

The circumference of a circle is 65?. In terms of pi, what is the area of the circle?

iVinArrow [24]

Answer:

1056.25π square units

Step-by-step explanation:

A few formulas an definitions which will help us:

(1) $\pi=\frac{c}{d}$ , where c is the circumference of a circle and d is its diameter

(2) $A=\pi r^2$ , where A is the area of a circle with radius r. To put it in terms of d, remember that a circle's diameter is simply twice its radius, or mathematically, (3) $d=2r \rightarrow r=\frac{d}{2}$ .

We can rearrange equation (1) to put d in terms of π and c, giving us (4) $d = \frac{c}{\pi}$ , and we can make a few substitutions in (2) using (3) and (4) to get use the area in terms of the circumference and π:

$A=\pi r^2\\=\pi\left(\frac{d}{2}\right)^2\\=\pi\left(\frac{d^2}{4}\right)\\=\pi\left(\frac{(c/\pi)^2}{4}\right)\\=\pi\left(\frac{c^2/\pi^2}{4}\right)\\=\pi\left(\frac{c^2}{4\pi^2}\right)\\\\=\frac{\pi c^2}{4\pi^2}\\ =\frac{c^2}{4\pi}$