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Savatey [412]
3 years ago
15

What other way can I represent 2 1/3 ?

Mathematics
2 answers:
il63 [147K]3 years ago
7 0
Decimal form- 2.333 (with the repeating sign on top)  or complete decimal form - 2.33333333
sveta [45]3 years ago
3 0
The following is also equivalent to 2 1/3:

2.33
7/3

Hope this helps, let me know if you have any other questions.


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Choose the correct comparison for the numbers below.
Alexandra [31]

Answer:

A

Step-by-step explanation:

In order to compare all three numbers, you must change them all to have the same form, either all decimal form, all fraction, or all percentages.

The easiest ways to compare are decimal and percentage, as they're practically the same thing. For simplicities sake, though, let's turn all the numbers into decimal.

Since 0.85 is already in decimal form, leave it as it is.

3/4 can be turned into a decimal by putting it into a calculator, but intuitively you should know that it's 0.75. If you don't know a fraction intuitively, you just need to make the fraction into a multiple of denominator 100 and take the numerator. For example:

\frac{3}{4} * \frac{25}{25} = \frac{75}{100}

Numerator is 75.0, now simply move the decimal place up to to get the decimal form 0.75.

91% can be changed into a decimal by moving the decimal place left 2 places. 91.0% turns into 0.91.

Now that you can see the numbers, just rearrange them from least to greatest

0.75<0.85<0.91

equal to A

5 0
3 years ago
For the system of equations that follows, use Gaussian elimination to obtain an equivalent system whose coefficient matrix is in
Rainbow [258]

Answer:

\begin{Vmatrix}1 & 0 & 0& 46/41 &180/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

Step-by-step explanation:

From the question we are told that

System of equations given as

x₁ + 3x₂ + x₃ + x₄ = 3;

2x₁ - 2x₂ + x₃ + 2x₄ = 8;

x₁ - 5x₂ + x₄ = 5

Matrix form

\begin{Vmatrix}1 & 3 & 1&1&3\\2 & -2 & 1&2&8\\0&1 & -5 & 1& 5\end{Vmatrix}  \begin{Vmatrix}x_1\\x_2\\x_3\\x_4\end{Vmatrix}

Generally the echelon reduction is mathematically applied as

\begin{Vmatrix}1 & 3 & 1&1&3\\2 & -2 & 1&2&8\\0&1 & -5 & 1& 5\end{Vmatrix}

Add -2 times the 1st row to the 2nd row

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & -8 & -1&0&2\\0&1 & -5 & 1& 5\end{Vmatrix}

Multiply the 2nd row by -1/8  

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&1 & -5 & 1& 5\end{Vmatrix}

Add -1 times the 2nd row to the 3rd row

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&0 & -41/8 & 1& 21/4\end{Vmatrix}

Multiply the 3rd row by -8/41

\begin{Vmatrix}1 & 3 & 1&1&3\\0 & 1 & 1/8&0&-1/4\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

Add -1/8 times the 3rd row to the 2nd row

Add -1 times the 3rd row to the 1st row

\begin{Vmatrix}1 & 3 & 0&49/41&165/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

Add -3 times the 2nd row to the 1st row

\begin{Vmatrix}1 & 0 & 0& 46/41 &180/41\\0 & 1 & 0&1/41 &-5/41\\0&0 & 1 & -8/41& -42/41\end{Vmatrix}

3 0
2 years ago
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