Answer:
The distance between B and lighthouse is 3.8688 km
Step-by-step explanation:
Given:
The angle made from ship to lighthouse is 36.5 degrees
and that of point B is 73 degrees.
To Find:
Distance Between Point B and Lighthouse
Solution:
<em>Consider a triangle LAB(Refer the attachment )</em>
And Point C is on the line AB as A i.e. ship is sailing to B
So C is at 5 km from A.
Now In triangle LAC,
Using Trigonometry Functions as ,
tan(36.5)=LC/AC
LC=tan(36.5)*AC
=0.7399*5
=3.6998 km
Now In triangle LBC,
As,
Sin(73)=LC/LB
LB=LC/(Sin(73))
=3.6998/0.9563
=3.8688 km
LB=3.8688 km
2((x+2)(x+2)}-4=28
2{x^2 + 4x + 4}-4=28
2x^2 +4x=28
2(x^2+2x)=28
x^2+2x=28/2
x^2+2x=14
Answer:
Step-by-step explanation:
we know that
In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, called the common difference
The formula for an Arithmetic Sequence is equal to
where
d is the common difference
n is the number of terms
a_1 is the first term of the sequence
In this problem we have
substitute
so
<u><em>Find the first ten terms</em></u>
For n=2 ----> 
For n=3 ----> 
For n=4 ----> 
For n=5 ----> 
For n=6 ----> 
For n=7 ----> 
For n=8 ----> 
For n=9 ----> 
For n=10 ----> 
The sequence is
Answer:
a <= 3
Step-by-step explanation:
Step 1. Factor out common terms in the first two terms, then in the last two terms.
2x^2(x - 5) -5(x - 5)
Step 2. Factor out the common term x - 5
(x - 5)(2x^2 - 5)
