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Cerrena [4.2K]
3 years ago
15

How do you write y=-4x2-16x-14 the 2 is an exponent

Mathematics
2 answers:
Natali5045456 [20]3 years ago
5 0

ax^2+bx+c=0 0 is the answer


Zepler [3.9K]3 years ago
3 0
4x^2+16x+14=0
I just transfered the given equation to the other side..that must be in a standard form where ax^2+bx+c=0
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I need help please.
GuDViN [60]

Answer:

The factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....

Step-by-step explanation:

The given expression is:

2q²-5pq-2q+5p

Make a pair of first two terms and last two terms:

(2q²-5pq) - (2q-5p)

Now factor out the common factor from each group.

Note that there is no common factor in second group. So we will take 1 as a common factor.

q(2q-5p) -1(2q-5p)

Now factor the polynomial by factoring out the G.C.F, 2q-5p

(2q-5p) (q-1)

Thus the factors of 2q²-5pq-2q+5p are (2q-5p) (q-1)....

4 0
3 years ago
3x+2y=4 <br>8x+5y=9<br><br>Please solve using Cross multiplication method.​
ch4aika [34]

Hello, Please refer the photo attachment for your question's answer. The final answer is :-

<u>x= -2, y= 5</u>

Hope it helps you...

Answered by Benjemin

3 0
2 years ago
1 . What is the distance between the two points. (0,5 1,3), (-0,4, -1,3) ?
Studentka2010 [4]

Answer:

Step-by-step explanation:

x1 = 0.5 x2 = -0.4 y1 = 1.3 y2 = -1.3

\sqrt{(x2 - x1)^{2}+(y2 - y1)^{2}

\sqrt{(-0.4 - 0.5)^{2}+(-1.3 - 1.3)^{2}

=2.75

6 0
3 years ago
How do you Evaluate?
slavikrds [6]
How do you evaluate: To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. In the example above, the variable x is equal to 6 since 6 + 6 = 12. If we know the value of our variables, we can replace the variables with their values and then evaluate the expression.
3 0
2 years ago
Write in slope-intercept form an equation of the line that passes through the points (−1,12) and (1,2).
zzz [600]

Answer:

y=-5x+7

Step-by-step explanation:

step 1

Find the slope

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have

the points (−1,12) and (1,2)

substitute

m=\frac{2-12}{1+1}

m=\frac{-10}{2}

m=-5

step 2

we know that

The equation of the line in slope intercept form is equl to

y=mx+b

where

m is the slope

b is the y-intercept

we have

m=-5

point\ (1,2)

substitute in the linear equation and solve for b

2=-5(1)+b

b=2+5=7

therefore

y=-5x+7

4 0
2 years ago
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