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alekssr [168]
3 years ago
14

The half price of helium-5 is 7.6 X 10 to the power of negative 22 seconds and the half-life helium -9 is 7 x 10 to the power of

negative 21-second approximately how many times greater is the half life of helium and -9 then that of helium -5
Mathematics
1 answer:
Digiron [165]3 years ago
5 0

Answer:

Approximately 9.211 times

Step-by-step explanation:

Given

x = 7.6 * 10^{-22}s --- half life of helium-5

y = 7 * 10^{-21}s --- half life of helium-9

Required

How many times greater is y than x

To do this, we simply divide y by x

\frac{y}{x} = \frac{7 * 10^{-21}s}{7.6 * 10^{-22}s}

\frac{y}{x} = \frac{7 * 10^{-21}}{7.6 * 10^{-22}}

Apply law of indices

\frac{y}{x} = \frac{7 * 10^{-21--22}}{7.6}

\frac{y}{x} = \frac{7 * 10^{-21+22}}{7.6}

\frac{y}{x} = \frac{7 * 10}{7.6}

\frac{y}{x} = \frac{70}{7.6}

\frac{y}{x} = 9.211

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