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3 years ago

Which of the following expressions is equal to 5^6/5^2

Mathematics

1 answer:

Natali5045456 [20]3 years ago

5 0

Answer:

$\dfrac{5^6}{5^2}$ = $5{\cdot}5{\cdot}5{\cdot}5$

Step-by-step explanation:

The given expression is :

$\dfrac{5^6}{5^2}$

We need to find this expression is equal to what.

$\dfrac{5^6}{5^2}=\dfrac{5^4\times 5^2}{5^2}\\\\=5^4\\\\=5\times 5\times 5\times 5\\\\\text{or}\\\\=5{\cdot}5{\cdot}5{\cdot}5$

Hence, $\dfrac{5^6}{5^2}$ is equal to $5{\cdot}5{\cdot}5{\cdot}5$ . Hence, the correct option is (c).

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Find equations of the spheres with center(3, −4, 5) that touch the following planes.a. xy-plane b. yz- plane c. xz-plane

postnew [5]

Answer:

(a) (x - 3)² + (y + 4)² + (z - 5)² = 25

(b) (x - 3)² + (y + 4)² + (z - 5)² = 9

Step-by-step explanation:

The equation of a sphere is given by:

(x - x₀)² + (y - y₀)² + (z - z₀)² = r² ---------------(i)

Where;

(x₀, y₀, z₀) is the center of the sphere

r is the radius of the sphere

Given:

Sphere centered at (3, -4, 5)

=> (x₀, y₀, z₀) = (3, -4, 5)

(a) To get the equation of the sphere when it touches the xy-plane, we do the following:

i. Since the sphere touches the xy-plane, it means the z-component of its centre is 0.

Therefore, we have the sphere now centered at (3, -4, 0).

Using the distance formula, we can get the distance d, between the initial points (3, -4, 5) and the new points (3, -4, 0) as follows;

$d = \sqrt{(3-3)^2+ (-4 - (-4))^2 + (0-5)^2}$

$d = \sqrt{(3-3)^2+ (-4 + 4)^2 + (0-5)^2}$

$d = \sqrt{(0)^2+ (0)^2 + (-5)^2}$

$d = \sqrt{(25)}$

d = 5

This distance is the radius of the sphere at that point. i.e r = 5

Now substitute this value r = 5 into the general equation of a sphere given in equation (i) above as follows;

(x - 3)² + (y - (-4))² + (z - 5)² = 5²

(x - 3)² + (y + 4)² + (z - 5)² = 25

Therefore, the equation of the sphere when it touches the xy plane is:

(x - 3)² + (y + 4)² + (z - 5)² = 25

(b) To get the equation of the sphere when it touches the yz-plane, we do the following:

i. Since the sphere touches the yz-plane, it means the x-component of its centre is 0.

Therefore, we have the sphere now centered at (0, -4, 5).

Using the distance formula, we can get the distance d, between the initial points (3, -4, 5) and the new points (0, -4, 5) as follows;

$d = \sqrt{(0-3)^2+ (-4 - (-4))^2 + (5-5)^2}$

$d = \sqrt{(-3)^2+ (-4 + 4)^2 + (5-5)^2}$

$d = \sqrt{(-3)^2 + (0)^2+ (0)^2}$

$d = \sqrt{(9)}$

d = 3

This distance is the radius of the sphere at that point. i.e r = 3

Now substitute this value r = 3 into the general equation of a sphere given in equation (i) above as follows;

(x - 3)² + (y - (-4))² + (z - 5)² = 3²

(x - 3)² + (y + 4)² + (z - 5)² = 9

Therefore, the equation of the sphere when it touches the yz plane is:

(x - 3)² + (y + 4)² + (z - 5)² = 9

(b) To get the equation of the sphere when it touches the xz-plane, we do the following:

i. Since the sphere touches the xz-plane, it means the y-component of its centre is 0.

Therefore, we have the sphere now centered at (3, 0, 5).

Using the distance formula, we can get the distance d, between the initial points (3, -4, 5) and the new points (3, 0, 5) as follows;

$d = \sqrt{(3-3)^2+ (0 - (-4))^2 + (5-5)^2}$

$d = \sqrt{(3-3)^2+ (0+4)^2 + (5-5)^2}$

$d = \sqrt{(0)^2 + (4)^2+ (0)^2}$

$d = \sqrt{(16)}$

d = 4

This distance is the radius of the sphere at that point. i.e r = 4

Now substitute this value r = 4 into the general equation of a sphere given in equation (i) above as follows;

(x - 3)² + (y - (-4))² + (z - 5)² = 4²

(x - 3)² + (y + 4)² + (z - 5)² = 16

Therefore, the equation of the sphere when it touches the xz plane is:

(x - 3)² + (y + 4)² + (z - 5)² = 16

3 0

3 years ago

Jada has 7/8 cup of cheese. Her cheese bread recipe calls for 1/6 cup of cheese. How many times can she make her recipe with the

riadik2000 [5.3K]

Divide (1/6 cup cheese) into (7/8 cup cheese):

7
--
8 7 6
----- = --- * --- = 42/8 = 5 2/8 = 5 1/4 = 5.25
1 8 1
--
6

She can prepare her recipe 5 times, with some material left over.

5 0

3 years ago

Find the points on the lemniscate where the tangent is horizontal. 8(x2 + y2)2 = 81(x2 − y2)

slamgirl [31]

The answers to this problem are:(±5√3/8,±5/8)Here is the solution:
Step 1: x2+y2=2516[2]x2+y2=2516[2]

Step 2: Substitute:
8(25/16)^2=25(x^2−y^2)
8(25/16)^2=25(x^2−y^2)
x^2−y^2=25/32.

Add [2] and [3]:
2x^2=75/32
x^2=75/74
x=±5√3/8
Substitute into [2]:
75/64+y^2=50/32
y^2=25/64
y=±5/8

3 0

3 years ago

Read 2 more answers

Consider the equation: -2x+5y=20

raketka [301]

Answer:

$- 2x + 5y = 20 \\ 5y = 2x + 20 \\ y = \frac{2}{5} x + 4 \\ slope = \frac{2}{5} \\ y - intercept = 4$

8 0

3 years ago

A biker rode 45 miles in 180 minutes. At what speed (in miles per hour) was the biker travelling? A. 4 B. 17 C. 9 D. 12

Anastasy [175]

Answer:

v = 15 miles / hour

Step-by-step explanation:

Given:

Distance covered by biker = s=45 miles

time taken by him = t=180 minutes

TO Find:

speed in miles per hour = v = ?

Solution:

As it is given that the distance covered is 45 miles

and time taken by him is 180 minutes

as one hour have 60 minutes

so time taken by rider = t = 180 /60

= 3 hours

this step is done because we have to find speed in miles per hour

Now

The formula for finding the distance is

distance = speed * time

s = v * t

we have to find v

so dividing both sides by t

$\frac{s}{t} = \frac{v*t}{t}$

it becomes

$v = \frac{s}{t}$

Putting the values

$v = \frac{45}{3}$

solving it gives

v = 15 miles / hour

which is the required speed

in the given options it is not available

5 0

3 years ago