H²+10h+21 = 0
h²+3h+7h+21 = 0
h(h+3)+7(h+3) = 0
(h+3)(h+7) = 0
h+3=0
h = -3
h+7=0
h=-7
        
             
        
        
        
Answer:
the second answer choice x greater than or equal to -6
Step-by-step explanation:
because u have to find the where the equation is defined. the range is the set  of values that correspond to the domain.
 
        
             
        
        
        
You could put,
 19
+ 6
———
 25
Then write, 
19+6=25
        
             
        
        
        
The answer would be : A parallelogram with congruent sides does NOT guarantee that a quadrilateral is a rectangle  
        
             
        
        
        
Answer:
work is attached and shown