X=27 and y=11
if you let each number equal x and y we know the sum is 38 so x+y=38
and the smaller is 16 less than the larger
. so if we say the smaller number is 7 then x-16=y
these can be solved as a simultaneous equation. x+(x-16)=38
2x-16=38
2x=54
x=27
(27)-16=y
y=11
so the answer is x=27 y=11
Yes, remember this 4 or less let it rest, 5 or more let it soar.
The answer is b hope this helps
Answer:
y=12
Step-by-step explanation:
y=2x ,so 2x=8x-x^2
x^2=8x-2x
x^2=6x
x^2/x=6x/x
x=6
y=2x ,2(6)
y=12
We can readily know the x^2-4x+4=3y then use it to replace the same function in the first equation which refers to the 3y+y^2-6y=0
y^2-3y=0
y(y-3)=0
y1=0 -----------y2=3
