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3 years ago

Help This step works because of the ______

Mathematics

2 answers:

lisov135 [29]3 years ago

5 0

I think it's 'b'. Sorry if I'm incorrect. ^^;

solong [7]3 years ago

5 0

This works because of the addition property of equality
a=16--->a+3=16+3
reverse engineering
a+3=16+3--->a=16
now given that 5x-4y=-30
and given also the equation 3x+4y=38
by the addition property
3x+4y+(-30)=38+(-30)
since -30=5x-4y by substituting
3x+4y+(5x-4y)=38-30
which yields
8x=8
the addition property of equality which is B.

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3 years ago

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bogdanovich [222]

Answer:

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3 years ago

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9966 [12]

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4 years ago

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liq [111]

$\text{Hello there!}\\\\\text{Solve for c:}\\\\2(5c -7) = 1\\\\\text{First, distribute the 2}\\\\10c-14=1\\\\\text{Add 14 to both sides}\\\\10c=15\\\\\text{Divide both sides by 10}\\\\c=1.5\\\\\boxed{\text{Answer: c = 1.5 or 3/2}}$

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3 years ago

h(x)= \dfrac{1}{8} x^3 - x^2h(x)= 8 1 x 3 −x 2 h, left parenthesis, x, right parenthesis, equals, start fraction, 1, divided b

Nesterboy [21]

Answer:

$\dfrac{1}{2}$

Step-by-step explanation:

Given the function $h(x)=\dfrac{1}{8}x^3-x^2$

The average rate of change of the function h(x) over the interval $a\le x\le b$ can be calculated using formula

$\dfrac{h(b)-h(a)}{b-a}$

In your case,

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so the average rate of change is

$\dfrac{h(2)-h(-2)}{2-(-2)}\\ \\=\dfrac{(\frac{1}{8}\cdot 2^3-2^2)-(\frac{1}{8}\cdot (-2)^3-(-2)^2)}{4}\\ \\=\dfrac{(1-4)-(-1-4)}{4}\\ \\=\dfrac{-3+5}{4}\\ \\=\dfrac{2}{4}\\ \\=\dfrac{1}{2}$

6 0

3 years ago