Step-by-step explanation:
When f(x) = f(x - 4), 3x² = 3(x - 4)².
=> x² = (x - 4)², x = -(x - 4), 2x = 4, x = 2.
The x-value is 2.
Answer:
Y'=3xy-3x-12
Y'=F(-2,-1)=0
Step-by-step explanation:
The function of the equation at the point (-2,-1)
is where the equation make the function go to zero:
Y'=3xy-3x-12
Y'=F(-2,-1)=[3(-2)(-1)]-[3(-1)]-12
F(-2,-1)=[6]-[-6]-12
F(-2,-1)=6+6-12
F(-2,-1)=12-12
F(-2,-1)=0
Solving for y
3xy-3x-12=0
y=4/x+x
Making y=0



So the values make the function go to zero
Answer:
what what's that's I can't understand anything
Y = 5
x = 5
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