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Tomtit [17]
2 years ago
8

Triangle PQR has coon instes (2.4), 0(-2,4), R(0,-6). Write the coordinates of the vertices of the image of a triangle afte aans

lation 3 units left and 1 unit up.
Mathematics
2 answers:
aliina [53]2 years ago
8 0
P’= (-1,5)
Q’=(-5,5)
R’=(-3,-5)
tatiyna2 years ago
8 0
(0,3) and (1,-3) cuz since it moves 4 units to the left it makes it negative 3 and 1 unit up
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6 0
2 years ago
Does anyone know the answer
Alex_Xolod [135]

Answer:x = 12,5

using thales's theorem, we have:

\frac{15}{15+36}=\frac{20}{6x-7}\\\\ 6x-7=\frac{20.(15+36)}{15}=68\\\\x = \frac{68+7}{6}=12.5

Step-by-step explanation:

8 0
2 years ago
The useful life of a radial tire is normally distributed with a mean of 30,000 miles and a standard deviation of 5000 miles. The
otez555 [7]

Answer:

  empirical rule: 81.5%

  table or calculator: 81.9%

Step-by-step explanation:

The lower limit of the life range of interest has a z-score of ...

  z = (x -μ)/σ = (20,000 -30,000)/5,000 = -2

The upper limit has a z-score of ...

  z = (35,000 -30,000)/5,000 = 1

<u>Empirical rule solution</u>

The empirical rule tells you that 95% of the distribution lies within 2 standard deviations of the mean, so (100% -95%)/2 = 2.5% lie below z = -2. It also tells you 68% lie within 1 standard deviation of the mean, so (100% -68%)/2 = 16% lie above z = 1.

The fraction that lies within -2 to 1 standard deviations of the means is thus ...

  (100% -2.5% -16%) = 81.5%

The probability the tire has a life in the desired range is about 81.5%.

__

<u>Calculator solution</u>

A probability calculator for the Normal distribution tells you that ...

  P(-2 < z < 1) ≈ 0.8185946

The probability the tire has a life in the desired range is about 81.9%.

6 0
2 years ago
8 out of the 20 balloons in a bunch are pink.
xeze [42]

Answer:

1/5

Step-by-step explanation:

8/20 divided by 4 equals 1/5

5 0
3 years ago
How long is JK?
-Dominant- [34]

Answer:

C) 3 times the sq root of 3

Step-by-step explanation:

In a right angle triangle, the COS is definned as the ajacent side over the hypotenuse. So

COS 60 = JK/JL

COS 60 = JK/(6*sq root 3)

.5 = JK/(6*3**1/2)

JK = .5 *(6*3**1/2)

JK = 3*3**1/2

5 0
2 years ago
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