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Alisiya [41]
3 years ago
6

Which equation describes a line with a slope of -8 and includes the point (-4, 7)?

Mathematics
1 answer:
timurjin [86]3 years ago
3 0
Such an equation would be y + 8x = - 25 (standard form) OR y = -8x - 25 (y-intercept form)
 
Deriving The Answer:

By using the point-slope form of the equation of a line, by knowing the gradient of that line and a point on that line, the equation of this line can be derived.

Now, the point-slope form exists as y - y₁ = m ( x - x₁)

since slope = -8 and the point on the line = (-4 , 7)

Then m = - 8
          x₁ = - 4
          y₁ =  7
                              ⇒  y - 7 = -8 ( x - (-4))

                              ⇒ y - 7 = -8x - 32

                              ⇒ y + 8x = - 25
                   


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£3 will buy 5 meals for one person.
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3/5 = $0.60 a meal for one person
4 0
3 years ago
A shape is made of 12 right triangles of equal size. Each right triangle has a base of 4 cm and a height of 5 cm. What is the to
Natalija [7]

Answer:

The total area of the shape is 120\ cm^{2}

Step-by-step explanation:

step 1

Find the area of one right triangle

The area of a triangle is equal to

A=\frac{1}{2}(b)(h)

we have

b=4\ cm

h=5\ cm

substitute

A=\frac{1}{2}(4)(5)=10\ cm^{2}

step 2

To find the total area of the shape multiply the area of one triangle by 12

so

A=12(10)=120\ cm^{2}

4 0
4 years ago
a. Find the linear approximating polynomial for the following function centered at the given point a. b. Find the quadratic appr
alekssr [168]

The polynomial approximate values are

a. The linear approximating polynomial is p1(x) = 2 - x

b.The quadratic approximating polynomial is  p2(x) = x² - 3*x + 3

c. The approximating polynomial value is p1(0.97) = 1.03; p2(0.97) = 1.0309

According to the statement

we have given that the f(x) = 1/x

And we have to find that polynomial approximate values which are written below

The linear approximating polynomial And quadratic approximating polynomial And approximate the given quantity of polynomials obtained in parts a. and b.

So, the given function is f(x) = 1/x

And

f'(x) =  -1/x²

f''(x) = 2/x³

a = 1

Now, we find the linear approximating polynomial

So,

a. The linear approximating polynomial is:

p1(x) = f(a) + f'(a)*(x - a)

p1(x) = 1/1 + -1/1² * (x - 1)

p1(x) = 1 - x + 1

p1(x) = 2 - x

And Now, we find the quadratic approximating polynomial

So,

b. The quadratic approximating polynomial is:

p2(x) = p1(x) + 1/2 * f''(a)*(x - a)²

p2(x) = 2 - x + 1/2 * 2/1³ * (x - 1)²

p2(x) = 2 - x + (x - 1)²

p2(x) = 2 - x + x² - 2*x + 1

p2(x) = x² - 3*x + 3

And Now, we find the approximating polynomial value

So,

c. approximate 1/0.97 using p1(x)

p1(0.97) = 2 - 0.97 = 1.03

approximate 1/0.97 using p2(x)

p2(0.97) = 0.97² - 3*0.97 + 3 = 1.0309

So, The polynomial approximate values are

a. The linear approximating polynomial is p1(x) = 2 - x

b.The quadratic approximating polynomial is  p2(x) = x² - 3*x + 3

c. The approximating polynomial value is p1(0.97) = 1.03; p2(0.97) = 1.0309.

Learn more about the polynomial approximate values here brainly.com/question/2595842

Disclaimer: This question was incomplete. Please find the full content below

Question:

A. Find the linear approximating polynomial for the following function centered at the given point a. b. Find the quadratic approximating polynomial for the following function centeredat the given point a. c. Use the polynomials obtained in parts a. and b. to approximate the given quantity.

f(x)=1/x, a=1; approximate 1/0.97

#SPJ4

3 0
2 years ago
A watch company is developing packaging for its new watch. The designer uses hexagons with a base area of 25 in squared and rect
WARRIOR [948]

Answer:

The volume of the prototype is V=250\ in^{3}

Step-by-step explanation:

we know that

The volume of a hexagonal prism is equal to

V=BH

where

B is the area of the hexagonal base

H is the length of the rectangular face

we have

B=25\ in^{2}

H=10\ in

substitute

V=(25)(10)

V=250\ in^{3}

7 0
3 years ago
Read 2 more answers
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