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neonofarm [45]
3 years ago
7

Find two consecutive odd integers such that 62 more than the lesser is five times the greater.

Mathematics
2 answers:
lidiya [134]3 years ago
8 0
Idk really know srry
irakobra [83]3 years ago
7 0
So, let’s define 2 consecutive odd integers:
3 and 5
5 and 7
7 and 9
9 and 11

So, our integers would be written as “x” and “x+2”.

Our solution:

x+62 = 5(x+2)
x+62 = 5x + 10
x - 5x = 10 - 62
-4x = -52
x = -52/-4
x = 13

So our integers are 13 and 15.



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bulgar [2K]
Hi there!

Diagonals of a rhombus bisect each other.

This means th't both the diagonals must have the same mid-point.

Hence, the midpt. of the diagonal through vertices.

by Mid-point formula :-

∴ [ \dfrac {-5 + 1}{2}, \dfrac {2 + 6}{2} ] = [ \dfrac {-6 + x}{2}, \dfrac {10 + y}{2} ]

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Therefore, Th' fourth vertex is (x, y) = (2, -2)

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~ Hope it helps!
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