Find two consecutive odd integers such that 62 more than the lesser is five times the greater.
2 answers:
So, let’s define 2 consecutive odd integers:
3 and 5
5 and 7
7 and 9
9 and 11
So, our integers would be written as “x” and “x+2”.
Our solution:
x+62 = 5(x+2)
x+62 = 5x + 10
x - 5x = 10 - 62
-4x = -52
x = -52/-4
x = 13
So our integers are 13 and 15.
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Step-by-step explanation:
m=y²-y¹/x²-x¹
m=5-1/7-1
m=4/6
m= 2/3
The slope is 2/3
9 x 9( 0+1)=
81(0+1)=
The answer is 81
Hope this helps!
can I pls get a brainleist?
I cannot help you sorry :/
That’s how you solve complex numbers.
0 , this is because it is a 6 sided die therefore it will be impossible to land on a 7