Find two consecutive odd integers such that 62 more than the lesser is five times the greater.
2 answers:
So, let’s define 2 consecutive odd integers:
3 and 5
5 and 7
7 and 9
9 and 11
So, our integers would be written as “x” and “x+2”.
Our solution:
x+62 = 5(x+2)
x+62 = 5x + 10
x - 5x = 10 - 62
-4x = -52
x = -52/-4
x = 13
So our integers are 13 and 15.
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