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neonofarm [45]
3 years ago
7

Find two consecutive odd integers such that 62 more than the lesser is five times the greater.

Mathematics
2 answers:
lidiya [134]3 years ago
8 0
Idk really know srry
irakobra [83]3 years ago
7 0
So, let’s define 2 consecutive odd integers:
3 and 5
5 and 7
7 and 9
9 and 11

So, our integers would be written as “x” and “x+2”.

Our solution:

x+62 = 5(x+2)
x+62 = 5x + 10
x - 5x = 10 - 62
-4x = -52
x = -52/-4
x = 13

So our integers are 13 and 15.



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erastova [34]
3y - 12 = -6
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 y = 2                  | Divide by 3 on both sides


Answer: y = 2 (Answer B)
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Anna71 [15]
Lets get started :)

f(x) = \frac{1}{9}x - 2
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This is the original equation, and now we have to find the inverse.

When finding the inverse, just flip the variables, x as y and y as x

f ⁻¹(x) 
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x = \frac{1}{9}y - 2
We have to isolate y as it is our f ⁻¹(x)

Take 2 to the other side { When you see subtraction, you do addition }
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7 0
3 years ago
-4 1/2 divided by - 2 2/3 as a mixed number
podryga [215]

Answer:

Exact Answer is 27/16

Decimal form: 1.6875

Mixed fraction 1 11/16    I assume that's what you need.

Step-by-step explanation:

27/16

Divide 27 by 16:

1 | 6 | 2 | 7

16 goes into 27 at most one time:

| | | 1

1 | 6 | 2 | 7

| - | 1 | 6

| | 1 | 1

Read off the results. The quotient is the number at the top and the remainder is the number at the bottom:

| | | 1 | (quotient)

1 | 6 | 2 | 7 |  

| - | 1 | 6 |  

| | 1 | 1 | (remainder)

The quotient of 27/16 is 1 with remainder 11, so:

Answer:  1 11/16

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Strike441 [17]

Answer:

The answer is 10

Step-by-step explanation:

because you will plus one if the decimal greater then or equal to 5

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