Answer:
60
Step-by-step explanation:
Tangents to a circle from a common external point are congruent, thus
JA = JB = 6
AL = KC = 11
CK = KB = 13
Thus
perimeter = 2(6) + 2(11) + 2(13) = 12 + 22 + 26 = 60
Answer:
Step-by-step explanation:
Let length = y width = x
y = 3x + 2
Perimeter = Sum of all sides (or sum of both lengths and both widths)
2y + 2x
2(3x + 2) + 2x
6x + 4 + 2x
8x + 4
Answer:
45 ways
Step-by-step explanation:
We are given;
there are 3 different math courses, 3 different science courses, and 5 different history courses.
Thus;
Number ways to take math course = 3
The number of ways to take science course = 3
The number of ways to take history course = 5
Now, if a student must take one of each course, the different ways it can be done is;
possible ways = 3 x 3 x 5 = 45 ways.
Thus, number of different ways in which a student must take one of each subject is 45 ways.
Pls. see attachment. I created that table for easy monitoring and understanding.
Yellow cells are sums that are even.
Orange cell are sums that are multiples of 3.
Yellow cells w/ orange texts are sums that are both even and multiples of 3.
Answer:
4(x) + 4(2)
Step-by-step explanation:
4(x+2) = 4(x) + 4(2)
Distribution property